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If the moment of a magnet is 400 C.G.S units, and the force acting on each pole in a uniform magnetic field of strength 0.32 oersted is 5.12 dynes. The distance between the poles of the magnet is equal to
  • a)
    25cm
  • b)
    16cm
  • c)
    12.5cm
  • d)
    12cm
Correct answer is option 'A'. Can you explain this answer?
Most Upvoted Answer
If the moment of a magnet is 400 C.G.S units, and the force acting on ...
Given:
Moment of magnet = 400 C.G.S units
Force acting on each pole in a uniform magnetic field of strength 0.32 oersted = 5.12 dynes

To find: The distance between the poles of the magnet

Formula used:
Force on each pole of a magnet, F = BIL
where B = magnetic field strength, I = current passing through the magnet, and L = length of the magnet

Calculation:
Let the distance between the poles of the magnet be 'd'
The moment of the magnet is given as 400 C.G.S units, which can be converted to Ampere-meter (A-m) using the conversion factor 10^-3, as follows:
Moment of magnet = 400 C.G.S units = 400 x 10^-3 A-m

Using the formula for force on each pole of a magnet, we have:
F = BIL
5.12 = 0.32 x (400 x 10^-3)/d
d = 0.32 x (400 x 10^-3)/5.12
d = 0.04/0.008
d = 5 cm

Thus, the distance between the poles of the magnet is 5 cm or 0.05 m, which is equal to option A.
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If the moment of a magnet is 400 C.G.S units, and the force acting on ...
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If the moment of a magnet is 400 C.G.S units, and the force acting on each pole in a uniform magnetic field of strength 0.32 oersted is 5.12 dynes. The distance between the poles of the magnet is equal toa) 25cm b) 16cm c) 12.5cm d) 12cm Correct answer is option 'A'. Can you explain this answer?
Question Description
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