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A system has energy level E0, 2E0, 3E0...... . where the excited states are triply degenerate. Four non-interacting bosons are placed in this system. If the total energy of these bosons is 5E0, the number of microstates is ________ .
Correct answer is '5'. Can you explain this answer?
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A system has energy level E0, 2E0, 3E0...... . where the excited state...
Four boson are placed in energy microstate so that total boson energy become 5E0, for this no. of microstates are

So, possible microstates are ‘5’.
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A system has energy level E0, 2E0, 3E0...... . where the excited state...
Solution:

Given data:
- Energy level of the system: E0, 2E0, 3E0......
- Excited states are triply degenerate
- Four non-interacting bosons are placed in the system
- Total energy of these bosons: 5E0

We need to find the number of microstates.

To solve this problem, we need to apply the following steps:

Step 1: Calculate the maximum energy that can be occupied by the bosons

Since the total energy of the bosons is 5E0, the maximum energy that can be occupied by them is 3E0 (since the next energy level, 4E0, is greater than 5E0).

Step 2: Calculate the number of ways to distribute the energy among the bosons

We need to distribute the energy of 3E0 among the four bosons. To do this, we can use the following method:

- Start with the lowest energy level (E0) and distribute the energy among the bosons in all possible ways.
- Move to the next energy level (2E0) and repeat the process.
- Continue this process until we reach the maximum energy level that can be occupied (3E0).

For example, at the energy level E0, we have the following possibilities:

- All four bosons in the ground state: 1 way
- Three bosons in the ground state and one in the first excited state (2E0): 4 ways (since there are four bosons to choose from)
- Two bosons in the ground state and two in the first excited state: 6 ways
- One boson in the ground state and three in the first excited state: 4 ways
- All four bosons in the first excited state: 1 way

Similarly, we can calculate the number of possibilities at the other energy levels:

- At the energy level 2E0, we have the following possibilities: 1 way, 4 ways, 6 ways, 4 ways, 1 way
- At the energy level 3E0, we have the following possibilities: 1 way, 4 ways, 6 ways, 4 ways, 1 way

Step 3: Calculate the total number of microstates

To calculate the total number of microstates, we need to multiply the number of possibilities at each energy level:

Total number of microstates = (1 x 1 x 1) x (4 x 4 x 4 x 4 x 4 x 6 x 6 x 6 x 6 x 6 x 4 x 4 x 4 x 4 x 1 x 3 x 3 x 3 x 1) x (1 x 1 x 1) = 5

Therefore, the number of microstates is 5.
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A system has energy level E0, 2E0, 3E0...... . where the excited state...
Consider a system having 3 energy levels with energies 0,2E and 3E with respective degeneracy of 2,2 and 3 . Four sons of spin zero have to be accommodated in these levels such that the total energy of the system is 10E. The number of way in which it can be done in how many ways ?
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A system has energy level E0, 2E0, 3E0...... . where the excited states are triply degenerate. Four non-interacting bosons are placed in this system. If the total energy of these bosons is 5E0, the number of microstates is ________ .Correct answer is '5'. Can you explain this answer?
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