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I. 35x² – 53x + 20 = 0
II. 56y² – 97y + 42 = 0
- a)यदि x > y
- b)यदि x > = y
- c)यदि x < y
- d)यदि x < = y
- e)यदि x = y या कोई संबंध स्थापित नहीं हो सकता
Correct answer is option 'C'. Can you explain this answer?
Verified Answer
I. 35x² – 53x + 20 = 0II. 56y² – 97y + 42 = 0a) ...
x = 5/7, 4/5|
y = 6/7, 7/8
y > x
y = 6/7, 7/8
y > x
Most Upvoted Answer
I. 35x² – 53x + 20 = 0II. 56y² – 97y + 42 = 0a) ...
Given Quadratic Equations:
I. 35x² – 53x + 20 = 0
II. 56y² – 97y + 42 = 0
Solution:
Step 1: Find the roots of the equations
To find the roots of the quadratic equations, we can use the quadratic formula:
For a quadratic equation of the form ax² + bx + c = 0, the roots are given by:
x = (-b ± √(b² - 4ac)) / 2a
For Equation I:
a = 35, b = -53, c = 20
Using the quadratic formula, we find the roots of Equation I as x = 1 and x = 20/35 = 4/7
For Equation II:
a = 56, b = -97, c = 42
Using the quadratic formula, we find the roots of Equation II as y = 6/7 and y = 1
Step 2: Compare the roots
Since the roots of Equation I are 1 and 4/7, and the roots of Equation II are 6/7 and 1, we can see that the roots of Equation I are smaller than the roots of Equation II.
Therefore, the correct answer is option C) x < /> because the roots of Equation I are less than the roots of Equation II.
I. 35x² – 53x + 20 = 0
II. 56y² – 97y + 42 = 0
Solution:
Step 1: Find the roots of the equations
To find the roots of the quadratic equations, we can use the quadratic formula:
For a quadratic equation of the form ax² + bx + c = 0, the roots are given by:
x = (-b ± √(b² - 4ac)) / 2a
For Equation I:
a = 35, b = -53, c = 20
Using the quadratic formula, we find the roots of Equation I as x = 1 and x = 20/35 = 4/7
For Equation II:
a = 56, b = -97, c = 42
Using the quadratic formula, we find the roots of Equation II as y = 6/7 and y = 1
Step 2: Compare the roots
Since the roots of Equation I are 1 and 4/7, and the roots of Equation II are 6/7 and 1, we can see that the roots of Equation I are smaller than the roots of Equation II.
Therefore, the correct answer is option C) x < /> because the roots of Equation I are less than the roots of Equation II.
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I. 35x² – 53x + 20 = 0II. 56y² – 97y + 42 = 0a) x > yb) x > = yc) x < yd) x < = ye)यदि x = y या कोई संबंध स्थापित नहीं हो सकताCorrect answer is option 'C'. Can you explain this answer? for Quant 2025 is part of Quant preparation. The Question and answers have been prepared according to the Quant exam syllabus. Information about I. 35x² – 53x + 20 = 0II. 56y² – 97y + 42 = 0a) x > yb) x > = yc) x < yd) x < = ye)यदि x = y या कोई संबंध स्थापित नहीं हो सकताCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for Quant 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for I. 35x² – 53x + 20 = 0II. 56y² – 97y + 42 = 0a) x > yb) x > = yc) x < yd) x < = ye)यदि x = y या कोई संबंध स्थापित नहीं हो सकताCorrect answer is option 'C'. Can you explain this answer?.
I. 35x² – 53x + 20 = 0II. 56y² – 97y + 42 = 0a) x > yb) x > = yc) x < yd) x < = ye)यदि x = y या कोई संबंध स्थापित नहीं हो सकताCorrect answer is option 'C'. Can you explain this answer? for Quant 2025 is part of Quant preparation. The Question and answers have been prepared according to the Quant exam syllabus. Information about I. 35x² – 53x + 20 = 0II. 56y² – 97y + 42 = 0a) x > yb) x > = yc) x < yd) x < = ye)यदि x = y या कोई संबंध स्थापित नहीं हो सकताCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for Quant 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for I. 35x² – 53x + 20 = 0II. 56y² – 97y + 42 = 0a) x > yb) x > = yc) x < yd) x < = ye)यदि x = y या कोई संबंध स्थापित नहीं हो सकताCorrect answer is option 'C'. Can you explain this answer?.
Solutions for I. 35x² – 53x + 20 = 0II. 56y² – 97y + 42 = 0a) x > yb) x > = yc) x < yd) x < = ye)यदि x = y या कोई संबंध स्थापित नहीं हो सकताCorrect answer is option 'C'. Can you explain this answer? in English & in Hindi are available as part of our courses for Quant.
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I. 35x² – 53x + 20 = 0II. 56y² – 97y + 42 = 0a) x > yb) x > = yc) x < yd) x < = ye)यदि x = y या कोई संबंध स्थापित नहीं हो सकताCorrect answer is option 'C'. Can you explain this answer?, a detailed solution for I. 35x² – 53x + 20 = 0II. 56y² – 97y + 42 = 0a) x > yb) x > = yc) x < yd) x < = ye)यदि x = y या कोई संबंध स्थापित नहीं हो सकताCorrect answer is option 'C'. Can you explain this answer? has been provided alongside types of I. 35x² – 53x + 20 = 0II. 56y² – 97y + 42 = 0a) x > yb) x > = yc) x < yd) x < = ye)यदि x = y या कोई संबंध स्थापित नहीं हो सकताCorrect answer is option 'C'. Can you explain this answer? theory, EduRev gives you an
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