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If î denotes a unit vector along incident light, r̂ a unit vector along refracted ray into medium of refractive index μ and n̂ a unit vector normal to the boundary of the media, directed towards incident medium, then the law of refraction can be written as
  • a)
    î.n̂=μ(r̂.n̂)
  • b)
    î×n̂=μ(n̂×r̂)
  • c)
    î×n̂=μ(r̂×n̂)
  • d)
    μ(î×n̂)=r̂×n̂
Correct answer is option 'C'. Can you explain this answer?
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If i denotes a unit vector along incident light, r a unit vector along...
N2 from a medium of refractive index n1, and θ1 and θ2 are the angles of incidence and refraction respectively, then the Snell's law of refraction is given by:

n1sinθ1 = n2sinθ2

where n1 and n2 are the refractive indices of the two media.

The incident and refracted rays lie in the same plane containing the normal to the interface between the two media. The angle of incidence θ1 is measured from the normal to the interface, while the angle of refraction θ2 is also measured from the normal, but in the opposite direction.

The unit vectors i and r can be expressed as:

i = sinθ1n + cosθ1m

r = sinθ2n + cosθ2m

where n and m are unit vectors normal and perpendicular to the plane of incidence respectively.

The direction of the refracted ray r depends on the angle of incidence θ1 and the refractive indices of the two media. If the angle of incidence is increased beyond a certain critical angle, the refracted ray is not possible and all the light is reflected back into the first medium. This phenomenon is called total internal reflection and is used in optical fibers for communication.
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If i denotes a unit vector along incident light, r a unit vector along...
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If i denotes a unit vector along incident light, r a unit vector along refracted ray into medium of refractive index μ and n a unit vector normal to the boundary of the media, directed towards incident medium, then the law of refraction can be written asa)i.n=μ(r.n)b)i×n=μ(n×r)c)i×n=μ(r×n)d)μ(i×n)=r×nCorrect answer is option 'C'. Can you explain this answer?
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If i denotes a unit vector along incident light, r a unit vector along refracted ray into medium of refractive index μ and n a unit vector normal to the boundary of the media, directed towards incident medium, then the law of refraction can be written asa)i.n=μ(r.n)b)i×n=μ(n×r)c)i×n=μ(r×n)d)μ(i×n)=r×nCorrect answer is option 'C'. Can you explain this answer? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about If i denotes a unit vector along incident light, r a unit vector along refracted ray into medium of refractive index μ and n a unit vector normal to the boundary of the media, directed towards incident medium, then the law of refraction can be written asa)i.n=μ(r.n)b)i×n=μ(n×r)c)i×n=μ(r×n)d)μ(i×n)=r×nCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for If i denotes a unit vector along incident light, r a unit vector along refracted ray into medium of refractive index μ and n a unit vector normal to the boundary of the media, directed towards incident medium, then the law of refraction can be written asa)i.n=μ(r.n)b)i×n=μ(n×r)c)i×n=μ(r×n)d)μ(i×n)=r×nCorrect answer is option 'C'. Can you explain this answer?.
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