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The magnitude of the magnetic dipole moment associated with a square shaped loop carrying a steady current I is m. If this loop is changed to a circular shape with the same current I passing through it, the magnetic dipole moment becomes nm. The value of n is _______ .
Correct answer is '1.27'. Can you explain this answer?
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The magnitude of the magnetic dipole moment associated with a square s...
Let the side of a square is a. 
then the magnetic moment m = La2
Now, magnetic dipole moment associated with the circular shaped loop 
carrying current I is m' = LπR2 
given that 2πR = 4a

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The magnitude of the magnetic dipole moment associated with a square s...
Given:
The magnetic dipole moment associated with a square shaped loop carrying current I is m.
The same current I passing through a circular shaped loop gives a magnetic dipole moment of nm.

To find:
The value of n.

Solution:
The magnetic dipole moment (m) of a current loop is given by the formula:

m = I * A * n

where I is the current, A is the area of the loop, and n is a constant that depends on the shape of the loop.

For a square loop, n = 1/2, since the magnetic field lines inside the loop cancel each other out, while the field lines outside the loop add up to form a dipole moment.

m = I * A * 1/2

For a circular loop, n = 1, since the magnetic field lines add up to form a dipole moment along the axis of the loop.

nm = I * πr^2 * 1

where r is the radius of the circular loop.

Dividing the two equations, we get:

nm/m = (I * πr^2)/(I * A * 1/2)

Simplifying, we get:

n = 2 * (r/A)

Substituting the given values, we get:

n = 2 * (πr^2/4)/(πd^2/2)

n = 1.27

Therefore, the value of n is 1.27.

Note: The magnetic dipole moment is a vector quantity, which means it has both magnitude and direction. The direction of the magnetic dipole moment depends on the direction of the current flow in the loop.
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The magnitude of the magnetic dipole moment associated with a square shaped loop carrying a steady current Iis m. If this loop is changed to a circular shape with the same current Ipassing through it, the magnetic dipole moment becomes nm. The value of n is _______ .Correct answer is '1.27'. Can you explain this answer?
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