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A 5 kg block is kept on a horizontal platform at rest. At time t = 0, the platform starts moving with a constant acceleration of 1 m /sec2. The coefficient of friction μ between the block and the platform is 0.2. The work done by the force of friction on the block in the fixed reference frame in 10 sec is _______ J.
Correct answer is '250'. Can you explain this answer?
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A 5 kg block is kept on a horizontal platform at rest. At time t = 0, ...
Assuming that the block does not slide on the platform
Ff = ma = 5 x 1 N
N - mg = 0 ⇒ N = mg = 50 N
The block will remain at rest relative to the platform
Displacement D relative to the ground =
work done by force of friction on the block = F.d = 250 J
Ff = ma = 5 x 1 N
N - mg = 0 ⇒ N = mg = 50 N
The block will remain at rest relative to the platform
Displacement D relative to the ground =
work done by force of friction on the block = F.d = 250 J
Most Upvoted Answer
A 5 kg block is kept on a horizontal platform at rest. At time t = 0, ...
Between the block and the platform is 0.2. What is the frictional force acting on the block?
To find the frictional force acting on the block, we first need to calculate the normal force.
The normal force is equal to the weight of the block, which can be calculated using the formula:
Weight = mass * acceleration due to gravity
Weight = 5 kg * 9.8 m/s^2
Weight = 49 N
The normal force is equal to the weight since the block is at rest on a horizontal platform.
The frictional force can be calculated using the formula:
Frictional force = coefficient of friction * normal force
Frictional force = 0.2 * 49 N
Frictional force = 9.8 N
Therefore, the frictional force acting on the block is 9.8 N.
To find the frictional force acting on the block, we first need to calculate the normal force.
The normal force is equal to the weight of the block, which can be calculated using the formula:
Weight = mass * acceleration due to gravity
Weight = 5 kg * 9.8 m/s^2
Weight = 49 N
The normal force is equal to the weight since the block is at rest on a horizontal platform.
The frictional force can be calculated using the formula:
Frictional force = coefficient of friction * normal force
Frictional force = 0.2 * 49 N
Frictional force = 9.8 N
Therefore, the frictional force acting on the block is 9.8 N.
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A 5 kg block is kept on a horizontal platform at rest. At time t = 0, the platform starts moving with a constant acceleration of 1 m /sec2. The coefficient of friction μbetween the block and the platform is 0.2. The work done by the force of friction on the block in the fixed reference frame in 10 sec is _______ J.Correct answer is '250'. Can you explain this answer?
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A 5 kg block is kept on a horizontal platform at rest. At time t = 0, the platform starts moving with a constant acceleration of 1 m /sec2. The coefficient of friction μbetween the block and the platform is 0.2. The work done by the force of friction on the block in the fixed reference frame in 10 sec is _______ J.Correct answer is '250'. Can you explain this answer? for GATE 2024 is part of GATE preparation. The Question and answers have been prepared according to the GATE exam syllabus. Information about A 5 kg block is kept on a horizontal platform at rest. At time t = 0, the platform starts moving with a constant acceleration of 1 m /sec2. The coefficient of friction μbetween the block and the platform is 0.2. The work done by the force of friction on the block in the fixed reference frame in 10 sec is _______ J.Correct answer is '250'. Can you explain this answer? covers all topics & solutions for GATE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A 5 kg block is kept on a horizontal platform at rest. At time t = 0, the platform starts moving with a constant acceleration of 1 m /sec2. The coefficient of friction μbetween the block and the platform is 0.2. The work done by the force of friction on the block in the fixed reference frame in 10 sec is _______ J.Correct answer is '250'. Can you explain this answer?.
A 5 kg block is kept on a horizontal platform at rest. At time t = 0, the platform starts moving with a constant acceleration of 1 m /sec2. The coefficient of friction μbetween the block and the platform is 0.2. The work done by the force of friction on the block in the fixed reference frame in 10 sec is _______ J.Correct answer is '250'. Can you explain this answer? for GATE 2024 is part of GATE preparation. The Question and answers have been prepared according to the GATE exam syllabus. Information about A 5 kg block is kept on a horizontal platform at rest. At time t = 0, the platform starts moving with a constant acceleration of 1 m /sec2. The coefficient of friction μbetween the block and the platform is 0.2. The work done by the force of friction on the block in the fixed reference frame in 10 sec is _______ J.Correct answer is '250'. Can you explain this answer? covers all topics & solutions for GATE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A 5 kg block is kept on a horizontal platform at rest. At time t = 0, the platform starts moving with a constant acceleration of 1 m /sec2. The coefficient of friction μbetween the block and the platform is 0.2. The work done by the force of friction on the block in the fixed reference frame in 10 sec is _______ J.Correct answer is '250'. Can you explain this answer?.
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