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Calculate the molality and mole fraction of solute in aqueous solution containing 3g urea (molar mass-60) per 250g of water?
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Calculate the molality and mole fraction of solute in aqueous solution...
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Calculate the molality and mole fraction of solute in aqueous solution...
Calculation of Molality and Mole Fraction of Urea in Aqueous Solution:

Step 1: Calculation of moles of Urea

Moles of Urea = Mass of Urea/Molar Mass of Urea
Moles of Urea = 3/60
Moles of Urea = 0.05

Step 2: Calculation of Mass of Solvent

Mass of Solvent = Mass of Water
Mass of Solvent = 250g

Step 3: Calculation of Molality of Urea

Molality (m) = Moles of Solute/Mass of Solvent (in kg)
Molality (m) = 0.05/0.25 (250g = 0.25kg)
Molality (m) = 0.2 mol/kg

Step 4: Calculation of Mole Fraction of Urea

Mole fraction (χ) = Moles of Urea/(Moles of Urea + Moles of Water)
Moles of Water = Mass of Water/Molar Mass of Water
Moles of Water = 250/18
Moles of Water = 13.89

Mole fraction (χ) = 0.05/(0.05 + 13.89)
Mole fraction (χ) = 0.0036

Final Answer:
The molality of Urea in the given solution is 0.2 mol/kg and the mole fraction of Urea is 0.0036.
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Calculate the molality and mole fraction of solute in aqueous solution containing 3g urea (molar mass-60) per 250g of water?
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