Calculation of Mole Fraction of Benzene in Solution containing 30% by Mass in Carbon Tetrachloride

Step 1: Determine the mass of Carbon Tetrachloride and Benzene in the solution.

Given that the solution consists of 30% by mass of Benzene, it means that the remaining 70% is Carbon Tetrachloride.

Let's assume we have 100 g of the solution, therefore:

- Mass of Benzene = 30 g
- Mass of Carbon Tetrachloride = 70 g

Step 2: Calculate the moles of each component in the solution.

To calculate the moles of each component, we need to divide the respective mass of each component by its molar mass.

Molar mass of Benzene (C6H6) = 6(12.01) + 6(1.01) = 78.11 g/mol
Molar mass of Carbon Tetrachloride (CCl4) = 12.01 + 4(35.45) = 153.82 g/mol

- Moles of Benzene = 30 g / 78.11 g/mol = 0.384 mol
- Moles of Carbon Tetrachloride = 70 g / 153.82 g/mol = 0.455 mol

Step 3: Calculate the mole fraction of Benzene in the solution.

Mole fraction = Moles of Benzene / Total moles of solution

Total moles of solution = Moles of Benzene + Moles of Carbon Tetrachloride

Total moles of solution = 0.384 mol + 0.455 mol = 0.839 mol

- Mole fraction of Benzene = 0.384 mol / 0.839 mol = 0.457

Therefore, the mole fraction of Benzene in a solution containing 30% by mass in Carbon Tetrachloride is 0.457.