An X molal solution of a compound in benzene has mole fraction equal t...
0.2 is the mole fraction of the solute in Benzene
Mole fraction of Benzene = 1-0.2 = 0.8
Molar mass of Benzene = 78 g/mol
Molality of solution = x
Molality can be found using the following formula:
m = (1000*x2) / (x1*M1)
x = (1000*0.2) / (0.8*78)
x = 3.205 moles/kg
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An X molal solution of a compound in benzene has mole fraction equal t...
Explanation:
To find the value of X, we need to understand the concepts of molality and mole fraction.
Molality:
Molality is a measure of the concentration of a solute in a solvent. It is defined as the number of moles of solute per kilogram of solvent. The formula for molality is:
Molality (m) = (moles of solute) / (mass of solvent in kg)
Mole Fraction:
Mole fraction is a way to express the concentration of a component in a mixture. It is the ratio of the number of moles of a component to the total number of moles in the mixture. The formula for mole fraction is:
Mole Fraction (χ) = (moles of component) / (total moles in mixture)
In this problem, we are given that the mole fraction of the compound in benzene is 0.2.
Calculating the Value of X:
To calculate the value of X, we can use the relationship between molality and mole fraction. The mole fraction of the compound can be expressed as:
χ = (moles of compound) / (moles of compound + moles of benzene)
We are also given that the compound is present in an X molal solution in benzene. This means that for every kilogram of benzene, there are X moles of the compound.
Using these relationships, we can set up the following equation:
0.2 = X / (X + 1)
Solving this equation will give us the value of X.
Solving the Equation:
To solve the equation, we can multiply both sides by (X + 1):
0.2(X + 1) = X
0.2X + 0.2 = X
0.8 = 0.8X
X = 1
Therefore, the value of X is 1.
An X molal solution of a compound in benzene has mole fraction equal t...
RELATION BETWEEN MOLE FRACTION AND MOLALITY:-
m=xb(solute) X 1000 / xa(solvent) X M.M of solvent
WHERE, xb= Mole fraction of solute xa= Mole fraction of solvent M.M= molecular mass of solvent
NOW, m= 0.2 X 1000 / 0.8 X 78. (since, 1-0.2=0.8) = 200/62.4 = 3.20512 molal
REMEBER THAT FORMULA , THATS EASIEST AND FASTEST WAY TO SOLVE QUESTIONS RELATED WITH MOLALITY AND MOLE FRACTION.
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