GATE Exam > GATE Questions > A hydraulic jump occurs, in a triangular (V-s...
Start Learning for Free
A hydraulic jump occurs, in a triangular (V-shaped) channel with side slopes 1:1 (vertical to horizontal). The sequent depths are 0.5 m and 1.5 m. The flow rate (in m3/s, round off to two decimal places) in the channel is _________.
Correct answer is '1.73'. Can you explain this answer?
| FREE This question is part of | Download PDF Attempt this Test |
Verified Answer
A hydraulic jump occurs, in a triangular (V-shaped) channel with side ...
For a horizontal and frictionless channel
Specific Force (F)
= Constant⇒
⇒
If Y1 and Y2 are conjugate depths
⇒
⇒
Q = 1.728 m3/sec
Most Upvoted Answer
A hydraulic jump occurs, in a triangular (V-shaped) channel with side ...
Given data:
- Side slopes of the triangular channel: 1:1 (vertical to horizontal)
- Sequent depths: 0.5 m and 1.5 m
Understanding a hydraulic jump:
- A hydraulic jump occurs when the flow changes from supercritical to subcritical.
- It is a sudden change in flow velocity and water depth.
- In a hydraulic jump, the flow energy is converted into turbulence and heat energy.
Equation for flow rate:
- The flow rate (Q) in a channel can be calculated using the equation Q = A * V, where A is the cross-sectional area and V is the velocity of flow.
Calculating the flow rate:
1. Calculate the cross-sectional areas of the two depths:
- Cross-sectional area at the first depth (A1) = (1/2) * b1 * y1, where b1 is the base width and y1 is the depth.
- Cross-sectional area at the second depth (A2) = (1/2) * b2 * y2, where b2 is the base width and y2 is the depth.
2. Calculate the base width:
- Since the side slopes are 1:1, the base width (b) can be calculated using the equation b = 2 * y, where y is the depth.
3. Calculate the velocities at the two depths:
- The velocity at the first depth (V1) can be calculated using the equation V1 = Q / A1.
- The velocity at the second depth (V2) can be calculated using the equation V2 = Q / A2.
4. Apply the energy equation:
- The energy equation for a hydraulic jump in a triangular channel is given by:
(V1^2 / (2g)) + (y1 - y2) = (V2^2 / (2g))
where g is the acceleration due to gravity (9.81 m/s^2).
5. Substitute the given values and solve for Q:
- (V1^2 / (2g)) + (y1 - y2) = (V2^2 / (2g))
- (Q^2 / (2g * A1^2)) + (y1 - y2) = (Q^2 / (2g * A2^2))
- (Q^2 / (2 * 9.81 * (0.5^2))) + (0.5 - 1.5) = (Q^2 / (2 * 9.81 * (1.5^2)))
- Simplifying the equation, we get: Q^2 = 1.73 * 9.81 * (0.5^2) * (1.5^2)
- Taking the square root of both sides, we get: Q ≈ 1.73 m^3/s
Therefore, the flow rate in the channel is approximately 1.73 m^3/s.
|
Explore Courses for GATE exam
|
|
Similar GATE Doubts
A hydraulic jump occurs, in a triangular (V-shaped) channel with side slopes 1:1 (vertical to horizontal). The sequent depths are 0.5 m and 1.5 m. The flow rate (in m3/s, round off to two decimal places) in the channel is _________.Correct answer is '1.73'. Can you explain this answer?
Question Description
A hydraulic jump occurs, in a triangular (V-shaped) channel with side slopes 1:1 (vertical to horizontal). The sequent depths are 0.5 m and 1.5 m. The flow rate (in m3/s, round off to two decimal places) in the channel is _________.Correct answer is '1.73'. Can you explain this answer? for GATE 2024 is part of GATE preparation. The Question and answers have been prepared according to the GATE exam syllabus. Information about A hydraulic jump occurs, in a triangular (V-shaped) channel with side slopes 1:1 (vertical to horizontal). The sequent depths are 0.5 m and 1.5 m. The flow rate (in m3/s, round off to two decimal places) in the channel is _________.Correct answer is '1.73'. Can you explain this answer? covers all topics & solutions for GATE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A hydraulic jump occurs, in a triangular (V-shaped) channel with side slopes 1:1 (vertical to horizontal). The sequent depths are 0.5 m and 1.5 m. The flow rate (in m3/s, round off to two decimal places) in the channel is _________.Correct answer is '1.73'. Can you explain this answer?.
A hydraulic jump occurs, in a triangular (V-shaped) channel with side slopes 1:1 (vertical to horizontal). The sequent depths are 0.5 m and 1.5 m. The flow rate (in m3/s, round off to two decimal places) in the channel is _________.Correct answer is '1.73'. Can you explain this answer? for GATE 2024 is part of GATE preparation. The Question and answers have been prepared according to the GATE exam syllabus. Information about A hydraulic jump occurs, in a triangular (V-shaped) channel with side slopes 1:1 (vertical to horizontal). The sequent depths are 0.5 m and 1.5 m. The flow rate (in m3/s, round off to two decimal places) in the channel is _________.Correct answer is '1.73'. Can you explain this answer? covers all topics & solutions for GATE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A hydraulic jump occurs, in a triangular (V-shaped) channel with side slopes 1:1 (vertical to horizontal). The sequent depths are 0.5 m and 1.5 m. The flow rate (in m3/s, round off to two decimal places) in the channel is _________.Correct answer is '1.73'. Can you explain this answer?.
Solutions for A hydraulic jump occurs, in a triangular (V-shaped) channel with side slopes 1:1 (vertical to horizontal). The sequent depths are 0.5 m and 1.5 m. The flow rate (in m3/s, round off to two decimal places) in the channel is _________.Correct answer is '1.73'. Can you explain this answer? in English & in Hindi are available as part of our courses for GATE.
Download more important topics, notes, lectures and mock test series for GATE Exam by signing up for free.
Here you can find the meaning of A hydraulic jump occurs, in a triangular (V-shaped) channel with side slopes 1:1 (vertical to horizontal). The sequent depths are 0.5 m and 1.5 m. The flow rate (in m3/s, round off to two decimal places) in the channel is _________.Correct answer is '1.73'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of
A hydraulic jump occurs, in a triangular (V-shaped) channel with side slopes 1:1 (vertical to horizontal). The sequent depths are 0.5 m and 1.5 m. The flow rate (in m3/s, round off to two decimal places) in the channel is _________.Correct answer is '1.73'. Can you explain this answer?, a detailed solution for A hydraulic jump occurs, in a triangular (V-shaped) channel with side slopes 1:1 (vertical to horizontal). The sequent depths are 0.5 m and 1.5 m. The flow rate (in m3/s, round off to two decimal places) in the channel is _________.Correct answer is '1.73'. Can you explain this answer? has been provided alongside types of A hydraulic jump occurs, in a triangular (V-shaped) channel with side slopes 1:1 (vertical to horizontal). The sequent depths are 0.5 m and 1.5 m. The flow rate (in m3/s, round off to two decimal places) in the channel is _________.Correct answer is '1.73'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice A hydraulic jump occurs, in a triangular (V-shaped) channel with side slopes 1:1 (vertical to horizontal). The sequent depths are 0.5 m and 1.5 m. The flow rate (in m3/s, round off to two decimal places) in the channel is _________.Correct answer is '1.73'. Can you explain this answer? tests, examples and also practice GATE tests.
|
|
Explore Courses for GATE exam
|
|
Suggested Free Tests
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
|
© EduRev
|
Education Revolution
|
|
Signup to see your scores
go up within 7 days!
Access 1000+ FREE Docs, Videos and Tests
Takes less than 10 seconds to signup