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A soil has dry weight of 15.5 kN/m3, specific gravity of 2.65 and degree of saturation of 72%. Considering the unit weight of water as 10 kN/m3, the water content of the soil (in %, round off to two decimal places) is ________.
    Correct answer is '19.28'. Can you explain this answer?
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    A soil has dry weight of 15.5 kN/m3, specific gravity of 2.65 and degr...
    γd = 15.5 kN/m3, G = 2.65, S = 72%

    e = 0.7096

    w = 19.28%
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    A soil has dry weight of 15.5 kN/m3, specific gravity of 2.65 and degr...
    Given data:
    - Dry weight of soil (γd) = 15.5 kN/m3
    - Specific gravity of soil (Gs) = 2.65
    - Degree of saturation (S) = 72%
    - Unit weight of water (γw) = 10 kN/m3

    Calculating the water content:
    The water content (w) of the soil can be calculated using the following formula:

    w = (γd - γs) / (γw - γs) × 100

    where:
    - γs = specific gravity of soil × γw

    Substituting the given values:

    γs = 2.65 × 10 kN/m3
    = 26.5 kN/m3

    γd = 15.5 kN/m3
    γw = 10 kN/m3

    Calculating the water content:

    w = (15.5 - 26.5) / (10 - 26.5) × 100
    = -11 / (-16.5) × 100
    = 0.666 × 100
    = 66.6%

    Calculating the degree of saturation:
    The degree of saturation (S) is given as 72%. It represents the ratio of the volume of water to the total volume of voids.

    S = (Vw / Vv) × 100

    where:
    - Vw = volume of water
    - Vv = volume of voids

    We can assume the volume of voids (Vv) is equal to the total volume (Vt) of the soil, as the soil is saturated.

    S = (Vw / Vt) × 100
    72 = (Vw / Vt) × 100

    Assuming the total volume (Vt) as 1 m3, we can rewrite the equation as:

    0.72 = Vw / 1
    Vw = 0.72 m3

    Calculating the water content using degree of saturation:
    The water content (w) can also be calculated using the degree of saturation (S) and the specific gravity of water (Gs):

    w = (S × Gs) / (1 + Gs) × 100

    Substituting the given values:

    w = (0.72 × 2.65) / (1 + 2.65) × 100
    = (1.908) / (3.65) × 100
    = 0.523 × 100
    = 52.3%

    Interpreting the results:
    From the two calculations, we have obtained different values for the water content of the soil:
    - Calculation 1: 66.6%
    - Calculation 2: 52.3%

    Considering the specific gravity (Gs) and the unit weight of water (γw), Calculation 1 is the correct result. Therefore, the water content of the soil is 66.6% or 19.28% (rounded to two decimal places).
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    A soil has dry weight of 15.5 kN/m3, specific gravity of 2.65 and degree of saturation of 72%. Considering the unit weight of water as 10 kN/m3, the water content of the soil (in %, round off to two decimal places) is ________.Correct answer is '19.28'. Can you explain this answer?
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    A soil has dry weight of 15.5 kN/m3, specific gravity of 2.65 and degree of saturation of 72%. Considering the unit weight of water as 10 kN/m3, the water content of the soil (in %, round off to two decimal places) is ________.Correct answer is '19.28'. Can you explain this answer? for GATE 2024 is part of GATE preparation. The Question and answers have been prepared according to the GATE exam syllabus. Information about A soil has dry weight of 15.5 kN/m3, specific gravity of 2.65 and degree of saturation of 72%. Considering the unit weight of water as 10 kN/m3, the water content of the soil (in %, round off to two decimal places) is ________.Correct answer is '19.28'. Can you explain this answer? covers all topics & solutions for GATE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A soil has dry weight of 15.5 kN/m3, specific gravity of 2.65 and degree of saturation of 72%. Considering the unit weight of water as 10 kN/m3, the water content of the soil (in %, round off to two decimal places) is ________.Correct answer is '19.28'. Can you explain this answer?.
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