Obviously HF which has the highest dielectric constant (K)value.the given compound NaBr is ionic compound .IONIC COMPOUNDS ARE GENERALLY SOLUBLE IN POLAR SOLVENTS.polar solvents have geeater" K" values.so 1 option is correct

Solubility of NaBr in Different Solvents
NaBr is an ionic compound composed of sodium (Na+) and bromide (Br-) ions. The solubility of NaBr depends on the ability of a solvent to dissociate the NaBr into its respective ions. The dielectric constant of a solvent is a measure of its ability to reduce the forces of attraction between ions in a compound.

1. HF (dielectric constant, k=120)
- HF has a high dielectric constant, indicating a strong ability to dissolve ionic compounds like NaBr. Therefore, NaBr is most likely to be highly soluble in HF.

2. H2SO4 (k=102)
- H2SO4 is a polar covalent compound but has a relatively high dielectric constant. It can dissolve some ionic compounds but may not be as effective as HF in dissolving NaBr.

3. H2O2 (k=98)
- H2O2 is a polar covalent compound with a high dielectric constant. It can dissolve some ionic compounds, including NaBr, but may not be as efficient as HF.

4. H2O (k=81)
- Water (H2O) is a polar solvent with a high dielectric constant. It can effectively dissolve NaBr due to its ability to separate the Na+ and Br- ions.

5. CH3OH (k=33)
- Methanol (CH3OH) is a polar solvent with a moderate dielectric constant. It can dissolve some ionic compounds, but its ability to dissolve NaBr may be lower compared to solvents with higher dielectric constants.

6. Benzene (k=3)
- Benzene is a nonpolar solvent with a low dielectric constant. It is not likely to dissolve ionic compounds like NaBr effectively.
In conclusion, NaBr is most soluble in solvents with high dielectric constants like HF, H2O, and H2O2 due to their strong ability to dissociate the ionic compound into its ions.