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In a drained tri-axial compression test, a sample of sand fails at deviator stress of 150 kPa under confining pressure of 50 kPa. The angle of internal friction (in degree, round off to the nearest integer) of the sample, is ________.
Correct answer is '37'. Can you explain this answer?
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In a drained tri-axial compression test, a sample of sand fails at dev...
Sand (C = 0); σd = 150; σ3 = 50; σ1 = 200
φ = 36.87°
So, the angle of internal friction to the nearest integer is 37°.
φ = 36.87°
So, the angle of internal friction to the nearest integer is 37°.
Most Upvoted Answer
In a drained tri-axial compression test, a sample of sand fails at dev...
Given information:
- Deviator stress (σd) = 150 kPa
- Confining pressure (σ3) = 50 kPa
Assumption:
- The sample is in a drained state, which means the pore water pressure is zero.
Concept of tri-axial compression test:
In a tri-axial compression test, a cylindrical sample of soil is subjected to a confining pressure (σ3) and axial stress (σ1). The axial stress is increased until failure occurs. The failure envelope is plotted on the deviator stress (σd) versus confining pressure (σ3) graph. The slope of this envelope gives the angle of internal friction (φ).
Calculating the angle of internal friction:
The deviator stress (σd) is given by the formula:
σd = σ1 - σ3
Since the pore water pressure is zero, the effective stress (σ') is equal to the total stress (σ). Thus, the axial stress (σ1) is equal to the sum of the deviator stress (σd) and the confining pressure (σ3).
σ1 = σd + σ3
Substituting the given values:
σd = 150 kPa
σ3 = 50 kPa
σ1 = 150 kPa + 50 kPa
= 200 kPa
The angle of internal friction (φ) can be determined using the formula:
tan(φ) = (σ1 - σ3) / (2 * σ3)
Substituting the given values:
tan(φ) = (200 kPa - 50 kPa) / (2 * 50 kPa)
= 150 kPa / 100 kPa
= 1.5
Taking the inverse tangent (tan^(-1)) of both sides:
φ = tan^(-1)(1.5)
≈ 56.31°
Rounding off to the nearest integer, the angle of internal friction is 56°.
Explanation of correct answer:
The correct answer given is 37°, which is different from the calculation. It is possible that the answer provided is incorrect, or there may be additional information or assumptions not mentioned in the given question. It is important to verify the given answer with reliable sources or consult the examiner for clarification.
- Deviator stress (σd) = 150 kPa
- Confining pressure (σ3) = 50 kPa
Assumption:
- The sample is in a drained state, which means the pore water pressure is zero.
Concept of tri-axial compression test:
In a tri-axial compression test, a cylindrical sample of soil is subjected to a confining pressure (σ3) and axial stress (σ1). The axial stress is increased until failure occurs. The failure envelope is plotted on the deviator stress (σd) versus confining pressure (σ3) graph. The slope of this envelope gives the angle of internal friction (φ).
Calculating the angle of internal friction:
The deviator stress (σd) is given by the formula:
σd = σ1 - σ3
Since the pore water pressure is zero, the effective stress (σ') is equal to the total stress (σ). Thus, the axial stress (σ1) is equal to the sum of the deviator stress (σd) and the confining pressure (σ3).
σ1 = σd + σ3
Substituting the given values:
σd = 150 kPa
σ3 = 50 kPa
σ1 = 150 kPa + 50 kPa
= 200 kPa
The angle of internal friction (φ) can be determined using the formula:
tan(φ) = (σ1 - σ3) / (2 * σ3)
Substituting the given values:
tan(φ) = (200 kPa - 50 kPa) / (2 * 50 kPa)
= 150 kPa / 100 kPa
= 1.5
Taking the inverse tangent (tan^(-1)) of both sides:
φ = tan^(-1)(1.5)
≈ 56.31°
Rounding off to the nearest integer, the angle of internal friction is 56°.
Explanation of correct answer:
The correct answer given is 37°, which is different from the calculation. It is possible that the answer provided is incorrect, or there may be additional information or assumptions not mentioned in the given question. It is important to verify the given answer with reliable sources or consult the examiner for clarification.
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In a drained tri-axial compression test, a sample of sand fails at deviator stress of 150 kPa under confining pressure of 50 kPa. The angle of internal friction (in degree, round off to the nearest integer) of the sample, is ________.Correct answer is '37'. Can you explain this answer?
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In a drained tri-axial compression test, a sample of sand fails at deviator stress of 150 kPa under confining pressure of 50 kPa. The angle of internal friction (in degree, round off to the nearest integer) of the sample, is ________.Correct answer is '37'. Can you explain this answer? for GATE 2024 is part of GATE preparation. The Question and answers have been prepared according to the GATE exam syllabus. Information about In a drained tri-axial compression test, a sample of sand fails at deviator stress of 150 kPa under confining pressure of 50 kPa. The angle of internal friction (in degree, round off to the nearest integer) of the sample, is ________.Correct answer is '37'. Can you explain this answer? covers all topics & solutions for GATE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for In a drained tri-axial compression test, a sample of sand fails at deviator stress of 150 kPa under confining pressure of 50 kPa. The angle of internal friction (in degree, round off to the nearest integer) of the sample, is ________.Correct answer is '37'. Can you explain this answer?.
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In a drained tri-axial compression test, a sample of sand fails at deviator stress of 150 kPa under confining pressure of 50 kPa. The angle of internal friction (in degree, round off to the nearest integer) of the sample, is ________.Correct answer is '37'. Can you explain this answer?, a detailed solution for In a drained tri-axial compression test, a sample of sand fails at deviator stress of 150 kPa under confining pressure of 50 kPa. The angle of internal friction (in degree, round off to the nearest integer) of the sample, is ________.Correct answer is '37'. Can you explain this answer? has been provided alongside types of In a drained tri-axial compression test, a sample of sand fails at deviator stress of 150 kPa under confining pressure of 50 kPa. The angle of internal friction (in degree, round off to the nearest integer) of the sample, is ________.Correct answer is '37'. Can you explain this answer? theory, EduRev gives you an
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