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In an 8085 microprocessor, the number of address lines required to access a 16 K byte memory bank is _________.
Correct answer is '14'. Can you explain this answer?
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Verified Answer
In an 8085 microprocessor, the number of address lines required to acc...
2n = N
n → Number of address lines
N → Number of Memory locations
∴ 2n = 16 kB
= 24(210) [∵ 1 kB = 210]
= 214
n = 14
n → Number of address lines
N → Number of Memory locations
∴ 2n = 16 kB
= 24(210) [∵ 1 kB = 210]
= 214
n = 14
Most Upvoted Answer
In an 8085 microprocessor, the number of address lines required to acc...
Explanation:
- The 8085 microprocessor has a 16-bit address bus.
- Therefore, the 8085 microprocessor can address up to 2^16 (64 K) memory locations.
- However, the 8085 microprocessor has only 8-bit data bus.
- Therefore, the 8085 microprocessor can transfer data in 8-bit chunks.
- To access a 16 K byte memory bank, we need to find the number of address lines required.
- 16 K byte memory bank means 16 * 1024 = 16384 bytes.
- 16384 bytes can be addressed by 2^14 (16384 = 2^14) memory locations.
- Therefore, to access a 16 K byte memory bank, we need 14 address lines.
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In an 8085 microprocessor, the number of address lines required to access a 16 K byte memory bank is _________.Correct answer is '14'. Can you explain this answer?
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