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A stone falls freely under gravity it covers distances h1,h2 and h3 in the first 5secs the next 5 secs and the next 5 secs respectively the relation between h1,h2and h3 is?
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A stone falls freely under gravity it covers distances h1,h2 and h3 in...
Relation between h1, h2, and h3 when a stone falls freely under gravity for 15 seconds:
When a stone falls freely under gravity, its motion is described by the equations of motion. The distance it covers in any given time depends on its initial velocity, which is zero when it is dropped from rest. The distance covered in the first 5 seconds is given by the equation:
h1 = (1/2)gt^2
where g is the acceleration due to gravity and t is the time taken. Substituting g = 9.8 m/s^2 and t = 5 s, we get:
h1 = (1/2)(9.8)(5)^2 = 122.5 m
Similarly, the distance covered in the next 5 seconds is given by:
h2 = h1 + (1/2)gt^2
Substituting g = 9.8 m/s^2 and t = 5 s, we get:
h2 = 122.5 + (1/2)(9.8)(5)^2 = 247.5 m
Finally, the distance covered in the last 5 seconds is given by:
h3 = h2 + (1/2)gt^2
Substituting g = 9.8 m/s^2 and t = 5 s, we get:
h3 = 247.5 + (1/2)(9.8)(5)^2 = 372.5 m
Therefore, the relation between h1, h2, and h3 is:
h3 = h2 + h1
Conclusion:
In conclusion, the distance covered by a stone falling freely under gravity depends on the time taken and the acceleration due to gravity. The relation between the distances covered in the first, second, and third 5-second intervals is given by h3 = h2 + h1.
Explanation:
When a stone falls freely under gravity, its motion is described by the equations of motion. The distance it covers in any given time depends on its initial velocity, which is zero when it is dropped from rest. The distance covered in the first 5 seconds is given by the equation:
h1 = (1/2)gt^2
where g is the acceleration due to gravity and t is the time taken. Substituting g = 9.8 m/s^2 and t = 5 s, we get:
h1 = (1/2)(9.8)(5)^2 = 122.5 m
Similarly, the distance covered in the next 5 seconds is given by:
h2 = h1 + (1/2)gt^2
Substituting g = 9.8 m/s^2 and t = 5 s, we get:
h2 = 122.5 + (1/2)(9.8)(5)^2 = 247.5 m
Finally, the distance covered in the last 5 seconds is given by:
h3 = h2 + (1/2)gt^2
Substituting g = 9.8 m/s^2 and t = 5 s, we get:
h3 = 247.5 + (1/2)(9.8)(5)^2 = 372.5 m
Therefore, the relation between h1, h2, and h3 is:
h3 = h2 + h1
Conclusion:
In conclusion, the distance covered by a stone falling freely under gravity depends on the time taken and the acceleration due to gravity. The relation between the distances covered in the first, second, and third 5-second intervals is given by h3 = h2 + h1.
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A stone falls freely under gravity it covers distances h1,h2 and h3 in...
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A stone falls freely under gravity it covers distances h1,h2 and h3 in the first 5secs the next 5 secs and the next 5 secs respectively the relation between h1,h2and h3 is?
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A stone falls freely under gravity it covers distances h1,h2 and h3 in the first 5secs the next 5 secs and the next 5 secs respectively the relation between h1,h2and h3 is? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about A stone falls freely under gravity it covers distances h1,h2 and h3 in the first 5secs the next 5 secs and the next 5 secs respectively the relation between h1,h2and h3 is? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A stone falls freely under gravity it covers distances h1,h2 and h3 in the first 5secs the next 5 secs and the next 5 secs respectively the relation between h1,h2and h3 is?.
A stone falls freely under gravity it covers distances h1,h2 and h3 in the first 5secs the next 5 secs and the next 5 secs respectively the relation between h1,h2and h3 is? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about A stone falls freely under gravity it covers distances h1,h2 and h3 in the first 5secs the next 5 secs and the next 5 secs respectively the relation between h1,h2and h3 is? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A stone falls freely under gravity it covers distances h1,h2 and h3 in the first 5secs the next 5 secs and the next 5 secs respectively the relation between h1,h2and h3 is?.
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