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A stone falls freely under gravity .it covers distances h1,h2,h3 in first 5 second ,the next 5 second and next 5 second respectively.the relation between h1,h2,h3 is?
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Relation between h1, h2 and h3 for a freely falling stone


Explanation


When a stone is dropped freely under gravity, it falls with a constant acceleration of 9.8 m/s². In the first 5 seconds, the stone covers a certain distance h1. In the next 5 seconds, it covers a distance h2, and in the next 5 seconds, it covers a distance h3.

Formula


The distance covered by the stone in any given time t can be calculated using the formula:

h = ½ * g * t²

where h is the distance covered, g is the acceleration due to gravity, and t is the time taken.

Calculation


Using the above formula, we can calculate the distances covered by the stone in the first 5 seconds, next 5 seconds, and the last 5 seconds.

Distance covered in the first 5 seconds:


h1 = ½ * g * t²

h1 = ½ * 9.8 * (5)²

h1 = 122.5 m

Distance covered in the next 5 seconds:


The stone starts from rest after the first 5 seconds. Hence, the distance covered in the next 5 seconds can be calculated as follows:

h2 = ½ * g * t²

h2 = ½ * 9.8 * (5)²

h2 = 122.5 m

Distance covered in the last 5 seconds:


Again, the stone starts from rest after the first 10 seconds. Hence, the distance covered in the last 5 seconds can be calculated as follows:

h3 = ½ * g * t²

h3 = ½ * 9.8 * (5)²

h3 = 122.5 m

Conclusion


Therefore, the relation between h1, h2, and h3 is that they are all equal and have a value of 122.5 meters.
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A stone falls freely under gravity .it covers distances h1,h2,h3 in first 5 second ,the next 5 second and next 5 second respectively.the relation between h1,h2,h3 is?
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