Let's assume that the body is thrown from point O with initial velocity u.

When the body reaches point A, it will have a velocity of u/2. This means that it has lost half of its initial velocity due to the gravitational force acting on it.

When the body reaches point B, it will have a velocity of u/3. This means that it has lost two-thirds of its initial velocity due to the gravitational force acting on it.

When the body reaches point C, it will have zero velocity. This is the highest point of its trajectory, also known as the maximum height.

After reaching point C, the body will start to fall back down to the ground. The same gravitational force that caused it to slow down on its way up will now cause it to speed up on its way down.

At point B, the body will have the same velocity u/3, but it will be moving in the opposite direction. As it continues to fall, its velocity will increase until it reaches point A, where it will have a velocity of u/2 in the downward direction.

Finally, when the body reaches point O again, it will have the same velocity u as when it was thrown upward, but in the downward direction. It will continue to fall until it reaches the ground.

So, the trajectory of the body can be represented graphically as follows:

^
|
u/2 |
|
|
u/3 |
|
|
| Maximum height (zero velocity)
|-----------------------------------> t
O A B C D

Ans : 20/7