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Which of the following photosynthetic bacteria have both PS-I and PS-II ?
- a)Green sulphur bacteria
- b)Purple-sulphur bacteria
- c)Purple non-sulphur bacteria
- d)Cyanobacteria
Correct answer is option 'D'. Can you explain this answer?
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Which of the following photosynthetic bacteria have both PS-I and PS-I...
Cyanobacteria- carry out oxygenic photosynthesis. Similar to plants they have PS1 and PS 2, use water as electron donor and generate oxygen
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Which of the following photosynthetic bacteria have both PS-I and PS-I...
Explanation:
Green sulphur bacteria, purple-sulphur bacteria, and purple non-sulphur bacteria only have either PS-I or PS-II, not both. On the other hand, cyanobacteria are the only photosynthetic bacteria that possess both PS-I and PS-II.
Details:
- Cyanobacteria: Cyanobacteria are gram-negative bacteria that perform oxygenic photosynthesis, similar to plants. They have both photosystem I (PS-I) and photosystem II (PS-II) in their thylakoid membranes, allowing them to carry out the complete process of photosynthesis.
- Green sulphur bacteria: These bacteria utilize sulfide ions for photosynthesis and only possess photosystem I (PS-I). They are typically found in anaerobic environments where hydrogen sulfide is present.
- Purple-sulphur bacteria: Purple-sulphur bacteria also use sulfide ions for photosynthesis, but they only have PS-II. They are commonly found in sulfur-rich environments like hot springs.
- Purple non-sulphur bacteria: These bacteria do not rely on sulfide ions for photosynthesis and only have PS-II. They can use various organic compounds as electron donors and are typically found in aquatic environments.
Therefore, among the mentioned photosynthetic bacteria, only cyanobacteria have both PS-I and PS-II, allowing them to efficiently carry out photosynthesis and produce oxygen as a byproduct.
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Which of the following photosynthetic bacteria have both PS-I and PS-II ?a)Green sulphur bacteriab)Purple-sulphur bacteriac)Purple non-sulphur bacteriad)CyanobacteriaCorrect answer is option 'D'. Can you explain this answer?
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