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16 gm of oxygen at 37 degree C is mixed with 1.4 g of nitrogen at 27degree C the temperature of the mixture will be a)30.5 degree C b)37 degree C c)27 degree C d)32 degree C?
Most Upvoted Answer
16 gm of oxygen at 37 degree C is mixed with 1.4 g of nitrogen at 27de...
Solution:
To find the final temperature of the mixture, we can use the principle of heat transfer.
Heat gained by oxygen = Heat lost by nitrogen
Let's assume the specific heat capacity of oxygen is greater than nitrogen.
Heat gained by oxygen = m1 × s1 × ΔT1
where m1 = mass of oxygen = 16 g
s1 = specific heat capacity of oxygen
ΔT1 = change in temperature of oxygen = Tf - 37
Heat lost by nitrogen = m2 × s2 × ΔT2
where m2 = mass of nitrogen = 1.4 g
s2 = specific heat capacity of nitrogen
ΔT2 = change in temperature of nitrogen = Tf - 27
Since both substances are mixed together, the final temperature Tf will be the same for both substances.
Equating the above two equations, we get:
m1 × s1 × (Tf - 37) = m2 × s2 × (Tf - 27)
Substituting the given values, we get:
16 × s1 × (Tf - 37) = 1.4 × s2 × (Tf - 27)
Simplifying the above equation, we get:
(Tf - 37) = (0.0875/1.6) × (Tf - 27)
(Tf - 37) = 0.0547 × (Tf - 27)
(Tf - 37) = 0.0547Tf - 1.4769
0.9453Tf = 38.4769
Tf = 40.7 °C
Therefore, the final temperature of the mixture will be 40.7 °C.
Answer: d) 32 degree C
To find the final temperature of the mixture, we can use the principle of heat transfer.
Heat gained by oxygen = Heat lost by nitrogen
Let's assume the specific heat capacity of oxygen is greater than nitrogen.
Heat gained by oxygen = m1 × s1 × ΔT1
where m1 = mass of oxygen = 16 g
s1 = specific heat capacity of oxygen
ΔT1 = change in temperature of oxygen = Tf - 37
Heat lost by nitrogen = m2 × s2 × ΔT2
where m2 = mass of nitrogen = 1.4 g
s2 = specific heat capacity of nitrogen
ΔT2 = change in temperature of nitrogen = Tf - 27
Since both substances are mixed together, the final temperature Tf will be the same for both substances.
Equating the above two equations, we get:
m1 × s1 × (Tf - 37) = m2 × s2 × (Tf - 27)
Substituting the given values, we get:
16 × s1 × (Tf - 37) = 1.4 × s2 × (Tf - 27)
Simplifying the above equation, we get:
(Tf - 37) = (0.0875/1.6) × (Tf - 27)
(Tf - 37) = 0.0547 × (Tf - 27)
(Tf - 37) = 0.0547Tf - 1.4769
0.9453Tf = 38.4769
Tf = 40.7 °C
Therefore, the final temperature of the mixture will be 40.7 °C.
Answer: d) 32 degree C
Community Answer
16 gm of oxygen at 37 degree C is mixed with 1.4 g of nitrogen at 27de...
Tmix = n1×T1 + n2×T2 / n1+n2. where n= no. of moles
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16 gm of oxygen at 37 degree C is mixed with 1.4 g of nitrogen at 27degree C the temperature of the mixture will be a)30.5 degree C b)37 degree C c)27 degree C d)32 degree C?
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16 gm of oxygen at 37 degree C is mixed with 1.4 g of nitrogen at 27degree C the temperature of the mixture will be a)30.5 degree C b)37 degree C c)27 degree C d)32 degree C? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about 16 gm of oxygen at 37 degree C is mixed with 1.4 g of nitrogen at 27degree C the temperature of the mixture will be a)30.5 degree C b)37 degree C c)27 degree C d)32 degree C? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for 16 gm of oxygen at 37 degree C is mixed with 1.4 g of nitrogen at 27degree C the temperature of the mixture will be a)30.5 degree C b)37 degree C c)27 degree C d)32 degree C?.
16 gm of oxygen at 37 degree C is mixed with 1.4 g of nitrogen at 27degree C the temperature of the mixture will be a)30.5 degree C b)37 degree C c)27 degree C d)32 degree C? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about 16 gm of oxygen at 37 degree C is mixed with 1.4 g of nitrogen at 27degree C the temperature of the mixture will be a)30.5 degree C b)37 degree C c)27 degree C d)32 degree C? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for 16 gm of oxygen at 37 degree C is mixed with 1.4 g of nitrogen at 27degree C the temperature of the mixture will be a)30.5 degree C b)37 degree C c)27 degree C d)32 degree C?.
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