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A uniform solid cylinderal roller of mass 'm' is being pulled on a horizontal surface with force F parallel to the surface and applied at its centre. If the acceleration of the cylinder is 'a' and it is rolling without slipping then the value of 'F' is:
- a)ma
- b)5/3 ma
- c)3/2 ma
- d)2 ma
Correct answer is option 'C'. Can you explain this answer?
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A uniform solid cylinderal roller of mass m is being pulled on a horiz...
Given:
Mass of the cylinder, m
Force applied at the centre, F
Acceleration of the cylinder, a
The cylinder is rolling without slipping.
To find: The value of F
Analysis:
When a force is applied to the centre of a cylinder, it starts to move forward with an acceleration a. The force also creates a torque about the centre of the cylinder, which tends to rotate it.
If the cylinder is rolling without slipping, then the force of friction acts between the cylinder and the surface. This force opposes the motion of the cylinder, and its magnitude is given by:
f = ma/2
where a is the acceleration of the cylinder.
The torque due to the force F is given by:
τ = F(R/2)
where R is the radius of the cylinder.
Since the cylinder is rolling without slipping, the torque τ should be equal to the torque due to the force of friction f. Therefore,
F(R/2) = ma/2
Solving for F, we get:
F = 3ma/2R
Therefore, the value of F is 3/2 times the product of mass, acceleration, and radius of the cylinder.
Answer: The correct option is (C) 3/2 ma
Mass of the cylinder, m
Force applied at the centre, F
Acceleration of the cylinder, a
The cylinder is rolling without slipping.
To find: The value of F
Analysis:
When a force is applied to the centre of a cylinder, it starts to move forward with an acceleration a. The force also creates a torque about the centre of the cylinder, which tends to rotate it.
If the cylinder is rolling without slipping, then the force of friction acts between the cylinder and the surface. This force opposes the motion of the cylinder, and its magnitude is given by:
f = ma/2
where a is the acceleration of the cylinder.
The torque due to the force F is given by:
τ = F(R/2)
where R is the radius of the cylinder.
Since the cylinder is rolling without slipping, the torque τ should be equal to the torque due to the force of friction f. Therefore,
F(R/2) = ma/2
Solving for F, we get:
F = 3ma/2R
Therefore, the value of F is 3/2 times the product of mass, acceleration, and radius of the cylinder.
Answer: The correct option is (C) 3/2 ma
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Community Answer
A uniform solid cylinderal roller of mass m is being pulled on a horiz...
Torque is equal to product of MOI and angular accleration . rolling without slipping means alpha is equal to a/R. SOLVE THIS U GET ANSWER AS 1.5a. AS UR ANSWER
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A uniform solid cylinderal roller of mass m is being pulled on a horizontal surface with force F parallel to the surface and applied at its centre. If the acceleration of the cylinder is a and it is rolling without slipping then the value of F is:a)mab)5/3 mac)3/2 mad)2 maCorrect answer is option 'C'. Can you explain this answer?
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A uniform solid cylinderal roller of mass m is being pulled on a horizontal surface with force F parallel to the surface and applied at its centre. If the acceleration of the cylinder is a and it is rolling without slipping then the value of F is:a)mab)5/3 mac)3/2 mad)2 maCorrect answer is option 'C'. Can you explain this answer? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about A uniform solid cylinderal roller of mass m is being pulled on a horizontal surface with force F parallel to the surface and applied at its centre. If the acceleration of the cylinder is a and it is rolling without slipping then the value of F is:a)mab)5/3 mac)3/2 mad)2 maCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A uniform solid cylinderal roller of mass m is being pulled on a horizontal surface with force F parallel to the surface and applied at its centre. If the acceleration of the cylinder is a and it is rolling without slipping then the value of F is:a)mab)5/3 mac)3/2 mad)2 maCorrect answer is option 'C'. Can you explain this answer?.
A uniform solid cylinderal roller of mass m is being pulled on a horizontal surface with force F parallel to the surface and applied at its centre. If the acceleration of the cylinder is a and it is rolling without slipping then the value of F is:a)mab)5/3 mac)3/2 mad)2 maCorrect answer is option 'C'. Can you explain this answer? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about A uniform solid cylinderal roller of mass m is being pulled on a horizontal surface with force F parallel to the surface and applied at its centre. If the acceleration of the cylinder is a and it is rolling without slipping then the value of F is:a)mab)5/3 mac)3/2 mad)2 maCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A uniform solid cylinderal roller of mass m is being pulled on a horizontal surface with force F parallel to the surface and applied at its centre. If the acceleration of the cylinder is a and it is rolling without slipping then the value of F is:a)mab)5/3 mac)3/2 mad)2 maCorrect answer is option 'C'. Can you explain this answer?.
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