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In a wheatstone bridge,all the four arms have equal resistance R. If the resistance of the galvanometer arm is also R, the the equivalent resistance of the combination as seen by the battery is?
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Introduction:
A Wheatstone bridge is a circuit used to measure unknown resistances by balancing the ratio of resistances in the arms of the bridge. It consists of a galvanometer, a battery, and four resistors arranged in a diamond shape. The principle behind a Wheatstone bridge is that when the bridge is balanced, the ratio of resistances in the arms is equal.
The Wheatstone Bridge Circuit:
The Wheatstone bridge circuit consists of four arms with equal resistances R and a galvanometer arm with resistance R. The circuit is connected to a battery.
Balancing the Bridge:
To balance the bridge, the galvanometer should show zero deflection (indicating that no current is flowing through it). This occurs when the ratio of resistances in the two arms of the bridge is equal.
Equivalent Resistance:
The equivalent resistance of a Wheatstone bridge can be calculated by considering the resistances in the arms. In this case, since all four arms have equal resistance R, the equivalent resistance can be found by analyzing the circuit.
Analysis:
Let's consider the resistances in the arms of the Wheatstone bridge circuit:
- Arm 1: Resistance R
- Arm 2: Resistance R
- Arm 3: Resistance R
- Arm 4: Resistance R
- Galvanometer Arm: Resistance R
Calculating Equivalent Resistance:
To calculate the equivalent resistance, we can start by considering two parallel arms at a time. Let's consider Arm 1 and Arm 2:
- Arm 1 and Arm 2 are in parallel, so their equivalent resistance is given by:
1/Req1 = 1/R + 1/R
= 2/R
Req1 = R/2
Similarly, considering Arm 3 and Arm 4:
- Arm 3 and Arm 4 are in parallel, so their equivalent resistance is given by:
1/Req2 = 1/R + 1/R
= 2/R
Req2 = R/2
Now, considering the parallel combination of Req1 and Req2:
- Req1 and Req2 are in parallel, so their equivalent resistance is given by:
1/Req = 1/Req1 + 1/Req2
= 1/(R/2) + 1/(R/2)
= 2/R + 2/R
= 4/R
Req = R/4
Conclusion:
The equivalent resistance of the Wheatstone bridge circuit, when all four arms have equal resistance R and the galvanometer arm also has resistance R, is R/4.
A Wheatstone bridge is a circuit used to measure unknown resistances by balancing the ratio of resistances in the arms of the bridge. It consists of a galvanometer, a battery, and four resistors arranged in a diamond shape. The principle behind a Wheatstone bridge is that when the bridge is balanced, the ratio of resistances in the arms is equal.
The Wheatstone Bridge Circuit:
The Wheatstone bridge circuit consists of four arms with equal resistances R and a galvanometer arm with resistance R. The circuit is connected to a battery.
Balancing the Bridge:
To balance the bridge, the galvanometer should show zero deflection (indicating that no current is flowing through it). This occurs when the ratio of resistances in the two arms of the bridge is equal.
Equivalent Resistance:
The equivalent resistance of a Wheatstone bridge can be calculated by considering the resistances in the arms. In this case, since all four arms have equal resistance R, the equivalent resistance can be found by analyzing the circuit.
Analysis:
Let's consider the resistances in the arms of the Wheatstone bridge circuit:
- Arm 1: Resistance R
- Arm 2: Resistance R
- Arm 3: Resistance R
- Arm 4: Resistance R
- Galvanometer Arm: Resistance R
Calculating Equivalent Resistance:
To calculate the equivalent resistance, we can start by considering two parallel arms at a time. Let's consider Arm 1 and Arm 2:
- Arm 1 and Arm 2 are in parallel, so their equivalent resistance is given by:
1/Req1 = 1/R + 1/R
= 2/R
Req1 = R/2
Similarly, considering Arm 3 and Arm 4:
- Arm 3 and Arm 4 are in parallel, so their equivalent resistance is given by:
1/Req2 = 1/R + 1/R
= 2/R
Req2 = R/2
Now, considering the parallel combination of Req1 and Req2:
- Req1 and Req2 are in parallel, so their equivalent resistance is given by:
1/Req = 1/Req1 + 1/Req2
= 1/(R/2) + 1/(R/2)
= 2/R + 2/R
= 4/R
Req = R/4
Conclusion:
The equivalent resistance of the Wheatstone bridge circuit, when all four arms have equal resistance R and the galvanometer arm also has resistance R, is R/4.
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In a wheatstone bridge,all the four arms have equal resistance R. If the resistance of the galvanometer arm is also R, the the equivalent resistance of the combination as seen by the battery is?
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In a wheatstone bridge,all the four arms have equal resistance R. If the resistance of the galvanometer arm is also R, the the equivalent resistance of the combination as seen by the battery is? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about In a wheatstone bridge,all the four arms have equal resistance R. If the resistance of the galvanometer arm is also R, the the equivalent resistance of the combination as seen by the battery is? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for In a wheatstone bridge,all the four arms have equal resistance R. If the resistance of the galvanometer arm is also R, the the equivalent resistance of the combination as seen by the battery is?.
In a wheatstone bridge,all the four arms have equal resistance R. If the resistance of the galvanometer arm is also R, the the equivalent resistance of the combination as seen by the battery is? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about In a wheatstone bridge,all the four arms have equal resistance R. If the resistance of the galvanometer arm is also R, the the equivalent resistance of the combination as seen by the battery is? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for In a wheatstone bridge,all the four arms have equal resistance R. If the resistance of the galvanometer arm is also R, the the equivalent resistance of the combination as seen by the battery is?.
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