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Cerium (Z=58) is an important member of lanthanoids. which of the following statement about cerium is incorrect?
- a)the cerium acts as an oxidising agent
- b)the oxidation states of cerium are +3 and +4
- c)The +4 oxidation state of cerium is not known in solutions.
- d)the +3 oxidation state of cerium is more stable than the +4 oxidation state
Correct answer is option 'C'. Can you explain this answer?
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Cerium (Z=58) is an important member of lanthanoids. which of the foll...
+4 is the most common oxidation state of cerium statement c is incorrect and option c is correct
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Cerium (Z=58) is an important member of lanthanoids. which of the foll...
The Incorrect Statement:
The incorrect statement about cerium is option 'C': The 4 oxidation state of cerium is not known in solutions.
Explanation:
Cerium is a member of the lanthanoid series, also known as the lanthanides, which are a group of 15 metallic elements with atomic numbers ranging from 57 (lanthanum) to 71 (lutetium). Cerium itself has an atomic number of 58.
Cerium as an Oxidizing Agent:
Cerium can act as an oxidizing agent, which means it can accept electrons from other substances in a chemical reaction. In its +4 oxidation state, cerium can oxidize other substances by transferring electrons to them. This property makes cerium useful in various applications, such as in self-cleaning ovens and catalytic converters.
Oxidation States of Cerium:
Cerium can exist in two main oxidation states: +3 and +4. In the +3 oxidation state, cerium has three valence electrons and has a stable electron configuration. This oxidation state is more commonly observed in cerium compounds.
In the +4 oxidation state, cerium has lost four valence electrons and has a different electron configuration. This oxidation state is less common but still important. Cerium compounds in the +4 oxidation state are often used as oxidizing agents.
The Unknown 4 Oxidation State in Solutions:
Contrary to option 'C', the +4 oxidation state of cerium is indeed known in solutions. Cerium(IV) compounds, such as ceric ammonium nitrate (CAN), can readily dissolve in water and form solutions that contain the Ce4+ ion. These solutions are commonly used in organic synthesis and redox reactions.
Stability of 3 and 4 Oxidation States:
The +3 oxidation state of cerium is generally more stable than the +4 oxidation state. This is because cerium has a higher tendency to lose three electrons rather than four, which allows it to achieve a stable electron configuration. However, under certain conditions and with appropriate oxidizing agents, cerium can be oxidized to the +4 oxidation state.
Conclusion:
The incorrect statement about cerium is option 'C': The 4 oxidation state of cerium is not known in solutions. In reality, the +4 oxidation state of cerium is known in solutions, and cerium compounds in this oxidation state are frequently used as oxidizing agents.
The incorrect statement about cerium is option 'C': The 4 oxidation state of cerium is not known in solutions.
Explanation:
Cerium is a member of the lanthanoid series, also known as the lanthanides, which are a group of 15 metallic elements with atomic numbers ranging from 57 (lanthanum) to 71 (lutetium). Cerium itself has an atomic number of 58.
Cerium as an Oxidizing Agent:
Cerium can act as an oxidizing agent, which means it can accept electrons from other substances in a chemical reaction. In its +4 oxidation state, cerium can oxidize other substances by transferring electrons to them. This property makes cerium useful in various applications, such as in self-cleaning ovens and catalytic converters.
Oxidation States of Cerium:
Cerium can exist in two main oxidation states: +3 and +4. In the +3 oxidation state, cerium has three valence electrons and has a stable electron configuration. This oxidation state is more commonly observed in cerium compounds.
In the +4 oxidation state, cerium has lost four valence electrons and has a different electron configuration. This oxidation state is less common but still important. Cerium compounds in the +4 oxidation state are often used as oxidizing agents.
The Unknown 4 Oxidation State in Solutions:
Contrary to option 'C', the +4 oxidation state of cerium is indeed known in solutions. Cerium(IV) compounds, such as ceric ammonium nitrate (CAN), can readily dissolve in water and form solutions that contain the Ce4+ ion. These solutions are commonly used in organic synthesis and redox reactions.
Stability of 3 and 4 Oxidation States:
The +3 oxidation state of cerium is generally more stable than the +4 oxidation state. This is because cerium has a higher tendency to lose three electrons rather than four, which allows it to achieve a stable electron configuration. However, under certain conditions and with appropriate oxidizing agents, cerium can be oxidized to the +4 oxidation state.
Conclusion:
The incorrect statement about cerium is option 'C': The 4 oxidation state of cerium is not known in solutions. In reality, the +4 oxidation state of cerium is known in solutions, and cerium compounds in this oxidation state are frequently used as oxidizing agents.
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Cerium (Z=58) is an important member of lanthanoids. which of the following statement about cerium is incorrect?a)the cerium acts as an oxidising agentb)the oxidation states of cerium are +3 and +4c)The +4 oxidation state of cerium is not known in solutions.d)the +3 oxidation state of cerium is more stable than the +4 oxidation stateCorrect answer is option 'C'. Can you explain this answer?
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Cerium (Z=58) is an important member of lanthanoids. which of the following statement about cerium is incorrect?a)the cerium acts as an oxidising agentb)the oxidation states of cerium are +3 and +4c)The +4 oxidation state of cerium is not known in solutions.d)the +3 oxidation state of cerium is more stable than the +4 oxidation stateCorrect answer is option 'C'. Can you explain this answer? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about Cerium (Z=58) is an important member of lanthanoids. which of the following statement about cerium is incorrect?a)the cerium acts as an oxidising agentb)the oxidation states of cerium are +3 and +4c)The +4 oxidation state of cerium is not known in solutions.d)the +3 oxidation state of cerium is more stable than the +4 oxidation stateCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Cerium (Z=58) is an important member of lanthanoids. which of the following statement about cerium is incorrect?a)the cerium acts as an oxidising agentb)the oxidation states of cerium are +3 and +4c)The +4 oxidation state of cerium is not known in solutions.d)the +3 oxidation state of cerium is more stable than the +4 oxidation stateCorrect answer is option 'C'. Can you explain this answer?.
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ample number of questions to practice Cerium (Z=58) is an important member of lanthanoids. which of the following statement about cerium is incorrect?a)the cerium acts as an oxidising agentb)the oxidation states of cerium are +3 and +4c)The +4 oxidation state of cerium is not known in solutions.d)the +3 oxidation state of cerium is more stable than the +4 oxidation stateCorrect answer is option 'C'. Can you explain this answer? tests, examples and also practice NEET tests.
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