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A ball falls freely from rest and the total distance covered by it in the last second of its motion is equal to the distance covered by it in first five seconds of its motion. the total time of the stone when it is in motion would be
Most Upvoted Answer
A ball falls freely from rest and the total distance covered by it in ...
**Explanation:**
Let's assume the total time of motion for the ball is *t* seconds. We need to find the value of *t*.
**Distance covered in the last second:**
The distance covered in the last second can be calculated using the equation of motion:
*s = ut + (1/2)at^2*
where:
- *s* is the distance covered
- *u* is the initial velocity (which is 0 in this case)
- *a* is the acceleration due to gravity (which is approximately 9.8 m/s^2)
- *t* is the time elapsed
Since the ball is falling freely, the acceleration due to gravity is acting in the downward direction. Therefore, the equation simplifies to:
*s = (1/2)gt^2*
where *g* is the acceleration due to gravity.
**Distance covered in the first five seconds:**
Similarly, the distance covered in the first five seconds can be calculated using the same equation of motion:
*s = (1/2)gt^2*
where *t* is the time elapsed (which is 5 seconds in this case).
**Equating the distances:**
According to the given condition, the distance covered in the last second is equal to the distance covered in the first five seconds:
*(1/2)gt^2 = (1/2)g(5)^2*
Simplifying the equation:
*t^2 = 5^2*
*t^2 = 25*
Taking the square root of both sides:
*t = 5*
Therefore, the total time of motion for the ball is 5 seconds.
**Conclusion:**
The total time of motion for the ball is 5 seconds.
Let's assume the total time of motion for the ball is *t* seconds. We need to find the value of *t*.
**Distance covered in the last second:**
The distance covered in the last second can be calculated using the equation of motion:
*s = ut + (1/2)at^2*
where:
- *s* is the distance covered
- *u* is the initial velocity (which is 0 in this case)
- *a* is the acceleration due to gravity (which is approximately 9.8 m/s^2)
- *t* is the time elapsed
Since the ball is falling freely, the acceleration due to gravity is acting in the downward direction. Therefore, the equation simplifies to:
*s = (1/2)gt^2*
where *g* is the acceleration due to gravity.
**Distance covered in the first five seconds:**
Similarly, the distance covered in the first five seconds can be calculated using the same equation of motion:
*s = (1/2)gt^2*
where *t* is the time elapsed (which is 5 seconds in this case).
**Equating the distances:**
According to the given condition, the distance covered in the last second is equal to the distance covered in the first five seconds:
*(1/2)gt^2 = (1/2)g(5)^2*
Simplifying the equation:
*t^2 = 5^2*
*t^2 = 25*
Taking the square root of both sides:
*t = 5*
Therefore, the total time of motion for the ball is 5 seconds.
**Conclusion:**
The total time of motion for the ball is 5 seconds.
Community Answer
A ball falls freely from rest and the total distance covered by it in ...
13 seconds.....
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A ball falls freely from rest and the total distance covered by it in the last second of its motion is equal to the distance covered by it in first five seconds of its motion. the total time of the stone when it is in motion would be
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A ball falls freely from rest and the total distance covered by it in the last second of its motion is equal to the distance covered by it in first five seconds of its motion. the total time of the stone when it is in motion would be for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about A ball falls freely from rest and the total distance covered by it in the last second of its motion is equal to the distance covered by it in first five seconds of its motion. the total time of the stone when it is in motion would be covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A ball falls freely from rest and the total distance covered by it in the last second of its motion is equal to the distance covered by it in first five seconds of its motion. the total time of the stone when it is in motion would be.
A ball falls freely from rest and the total distance covered by it in the last second of its motion is equal to the distance covered by it in first five seconds of its motion. the total time of the stone when it is in motion would be for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about A ball falls freely from rest and the total distance covered by it in the last second of its motion is equal to the distance covered by it in first five seconds of its motion. the total time of the stone when it is in motion would be covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A ball falls freely from rest and the total distance covered by it in the last second of its motion is equal to the distance covered by it in first five seconds of its motion. the total time of the stone when it is in motion would be.
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