Given information:
Mass of the body (m) = 5 kg
Angle of the inclined plane (θ) = 60 degrees
Coefficient of friction (µ) = 0.2
Distance traveled (d) = 2 m

Solution:

1. Find the normal force (N)
The normal force is the force exerted by the surface on the body perpendicular to the surface. It can be calculated using the formula:

N = mg cos(θ)

Here, g is the acceleration due to gravity (approximately 9.8 m/s^2). Plugging in the values, we get:

N = 5 kg * 9.8 m/s^2 * cos(60 degrees)
N = 24.5 N

2. Find the force of gravity (mg)
The force of gravity is the weight of the body and can be calculated using the formula:

mg = 5 kg * 9.8 m/s^2
mg = 49 N

3. Find the force of friction (f)
The force of friction can be calculated using the formula:

f = µN

Plugging in the values, we get:

f = 0.2 * 24.5 N
f = 4.9 N

4. Find the component of the force of gravity along the incline (F_parallel)
The component of the force of gravity along the incline can be calculated using the formula:

F_parallel = mg sin(θ)

Plugging in the values, we get:

F_parallel = 49 N * sin(60 degrees)
F_parallel = 42.43 N

5. Find the work done (W)
The work done is the product of the force applied and the distance traveled. In this case, the net force acting on the body is the difference between the parallel force and the force of friction.

Net force (F_net) = F_parallel - f = 42.43 N - 4.9 N = 37.53 N

The work done can be calculated using the formula:

W = F_net * d * cos(θ)

Plugging in the values, we get:

W = 37.53 N * 2 m * cos(60 degrees)
W = 75.06 J

Therefore, the work done in pulling the body along the inclined plane through 2 m is 75.06 Joules.