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A block of mass 10 kg 10 kg is placed on inclined plane making an angle angle of 30 degree With the horizontal. If the coefficient of friction between the block and the plane is 0.3. What is the force of friction acting on the block?
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A block of mass 10 kg 10 kg is placed on inclined plane making an angl...
Understanding the Forces on the Inclined Plane
To calculate the force of friction acting on the block, we need to analyze the forces acting on it due to gravity, normal force, and friction.
1. Forces Acting on the Block
- Weight of the Block (W): The weight can be calculated using W = mg, where m = 10 kg and g = 9.81 m/s².
- Inclined Angle: The angle of inclination is 30 degrees.
2. Components of Weight
- Parallel Component (W_parallel): This is the component of weight acting down the incline.
- W_parallel = W * sin(θ) = (10 kg * 9.81 m/s²) * sin(30°) = 49.05 N.
- Perpendicular Component (W_perpendicular): This is the component of weight acting perpendicular to the incline.
- W_perpendicular = W * cos(θ) = (10 kg * 9.81 m/s²) * cos(30°) = 84.87 N.
3. Normal Force (N)
- The normal force is equal to the perpendicular component of the weight:
- N = W_perpendicular = 84.87 N.
4. Calculating the Force of Friction (F_friction)
- Frictional Force Formula: F_friction = μ * N, where μ is the coefficient of friction (0.3).
- Using the normal force calculated:
- F_friction = 0.3 * 84.87 N = 25.46 N.
Conclusion
The force of friction acting on the block placed on the inclined plane is approximately 25.46 N. This frictional force will act up the incline, opposing the motion of the block.
To calculate the force of friction acting on the block, we need to analyze the forces acting on it due to gravity, normal force, and friction.
1. Forces Acting on the Block
- Weight of the Block (W): The weight can be calculated using W = mg, where m = 10 kg and g = 9.81 m/s².
- Inclined Angle: The angle of inclination is 30 degrees.
2. Components of Weight
- Parallel Component (W_parallel): This is the component of weight acting down the incline.
- W_parallel = W * sin(θ) = (10 kg * 9.81 m/s²) * sin(30°) = 49.05 N.
- Perpendicular Component (W_perpendicular): This is the component of weight acting perpendicular to the incline.
- W_perpendicular = W * cos(θ) = (10 kg * 9.81 m/s²) * cos(30°) = 84.87 N.
3. Normal Force (N)
- The normal force is equal to the perpendicular component of the weight:
- N = W_perpendicular = 84.87 N.
4. Calculating the Force of Friction (F_friction)
- Frictional Force Formula: F_friction = μ * N, where μ is the coefficient of friction (0.3).
- Using the normal force calculated:
- F_friction = 0.3 * 84.87 N = 25.46 N.
Conclusion
The force of friction acting on the block placed on the inclined plane is approximately 25.46 N. This frictional force will act up the incline, opposing the motion of the block.
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A block of mass 10 kg 10 kg is placed on inclined plane making an angle angle of 30 degree With the horizontal. If the coefficient of friction between the block and the plane is 0.3. What is the force of friction acting on the block?
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A block of mass 10 kg 10 kg is placed on inclined plane making an angle angle of 30 degree With the horizontal. If the coefficient of friction between the block and the plane is 0.3. What is the force of friction acting on the block? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about A block of mass 10 kg 10 kg is placed on inclined plane making an angle angle of 30 degree With the horizontal. If the coefficient of friction between the block and the plane is 0.3. What is the force of friction acting on the block? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A block of mass 10 kg 10 kg is placed on inclined plane making an angle angle of 30 degree With the horizontal. If the coefficient of friction between the block and the plane is 0.3. What is the force of friction acting on the block?.
A block of mass 10 kg 10 kg is placed on inclined plane making an angle angle of 30 degree With the horizontal. If the coefficient of friction between the block and the plane is 0.3. What is the force of friction acting on the block? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about A block of mass 10 kg 10 kg is placed on inclined plane making an angle angle of 30 degree With the horizontal. If the coefficient of friction between the block and the plane is 0.3. What is the force of friction acting on the block? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A block of mass 10 kg 10 kg is placed on inclined plane making an angle angle of 30 degree With the horizontal. If the coefficient of friction between the block and the plane is 0.3. What is the force of friction acting on the block?.
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