Under isothermal condition, a gas at 300K expands from 0.1 L to 0.25 L...
Calculation of Work Done by GasGiven:
- Initial volume (Vi) = 0.1 L
- Final volume (Vf) = 0.25 L
- External pressure (P) = 2 bar
- Temperature (T) = 300K
- 1 L bar = 100 J
Since the process is isothermal, the temperature remains constant.
Formula:Work done by a gas during isothermal expansion can be calculated using the formula:
W = nRT ln(Vf/Vi)
Where,
- n = number of moles of gas
- R = gas constant = 8.314 J/mol K
- T = temperature in Kelvin
First, we need to calculate the number of moles of gas.
Calculation of Number of Moles of GasFormula:
n = PV/RT
Where,
- P = external pressure
- V = final volume
- R = gas constant
- T = temperature in Kelvin
Substituting the given values, we get:
n = (2 x 0.25)/ (8.314 x 300 x 10-3) = 0.01002 mol
Now, we can substitute the values of n, R, T, Vf, and Vi in the formula for work done.
Substitution of Values in FormulaW = nRT ln(Vf/Vi)
W = (0.01002) x (8.314) x (300) x ln(0.25/0.1)
W = 62.75 J
Since 1 L bar = 100 J, we can convert the answer into L bar units.
Work Done by Gas in L bar unitsW = 62.75/100 = 0.6275 L bar
Therefore, the work done by the gas is 0.6275 L bar or 62.75 J.