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Under isothermal condition, a gas at 300K expands from 0.1 L to 0.25 L against a constant external pressure of 2 bar. The work done by the gas is (Given that 1 L bar = 100 J)?
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Under isothermal condition, a gas at 300K expands from 0.1 L to 0.25 L...
Calculation of Work Done by Gas

Given:


  • Initial volume (Vi) = 0.1 L

  • Final volume (Vf) = 0.25 L

  • External pressure (P) = 2 bar

  • Temperature (T) = 300K

  • 1 L bar = 100 J



Since the process is isothermal, the temperature remains constant.


Formula:
Work done by a gas during isothermal expansion can be calculated using the formula:

W = nRT ln(Vf/Vi)

Where,


  • n = number of moles of gas

  • R = gas constant = 8.314 J/mol K

  • T = temperature in Kelvin



First, we need to calculate the number of moles of gas.


Calculation of Number of Moles of Gas

Formula:

n = PV/RT

Where,


  • P = external pressure

  • V = final volume

  • R = gas constant

  • T = temperature in Kelvin



Substituting the given values, we get:

n = (2 x 0.25)/ (8.314 x 300 x 10-3) = 0.01002 mol


Now, we can substitute the values of n, R, T, Vf, and Vi in the formula for work done.


Substitution of Values in Formula

W = nRT ln(Vf/Vi)

W = (0.01002) x (8.314) x (300) x ln(0.25/0.1)

W = 62.75 J


Since 1 L bar = 100 J, we can convert the answer into L bar units.


Work Done by Gas in L bar units

W = 62.75/100 = 0.6275 L bar


Therefore, the work done by the gas is 0.6275 L bar or 62.75 J.
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Under isothermal condition, a gas at 300K expands from 0.1 L to 0.25 L...
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Under isothermal condition, a gas at 300K expands from 0.1 L to 0.25 L against a constant external pressure of 2 bar. The work done by the gas is (Given that 1 L bar = 100 J)?
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