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Under isothermal condition a gas at 300 Kelvin expanded from 0.1 litre to 0.25 against a constant external pressure of 2bar the work done by the gas is ?given that 1 litre bar is equal 100J?
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Under isothermal condition a gas at 300 Kelvin expanded from 0.1 litre...
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Under isothermal condition a gas at 300 Kelvin expanded from 0.1 litre...
Understanding the Problem
To calculate the work done by the gas during an isothermal expansion, we can use the formula for work done against a constant external pressure:
Work Done (W) = - P_ext × ΔV
Where:
- P_ext = External pressure
- ΔV = Change in volume
Given Data
- Initial Volume (V1) = 0.1 L
- Final Volume (V2) = 0.25 L
- External Pressure (P_ext) = 2 bar
- 1 L bar = 100 J
Calculating Change in Volume (ΔV)
- ΔV = V2 - V1
- ΔV = 0.25 L - 0.1 L = 0.15 L
Converting to Bar
Since the external pressure is given in bar, we can use the volume in liters directly with the conversion factor:
Calculating Work Done
- Work Done (W) = - P_ext × ΔV
- W = - 2 bar × 0.15 L
Now, convert the result into joules:
- W = - 2 × 0.15 × 100 J
- W = - 30 J
Conclusion
The negative sign indicates that work is done by the gas on the surroundings during expansion.
Thus, the work done by the gas is 30 J.
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Under isothermal condition a gas at 300 Kelvin expanded from 0.1 litre to 0.25 against a constant external pressure of 2bar the work done by the gas is ?given that 1 litre bar is equal 100J?
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