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A triangular block of mass M with angles 30°, 60° and 90° rest with its 30° - 90° side on a horizontal table. A cubical block of mass m rests on 60° - 30° side. The acceleration which M must have relative to the table to keep m stationary relative to the triangular block is (assuming frictionless contact)a)gb)g/√2c)g/√3d)g/√5Correct answer is option 'C'. Can you explain this answer? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared
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the NEET exam syllabus. Information about A triangular block of mass M with angles 30°, 60° and 90° rest with its 30° - 90° side on a horizontal table. A cubical block of mass m rests on 60° - 30° side. The acceleration which M must have relative to the table to keep m stationary relative to the triangular block is (assuming frictionless contact)a)gb)g/√2c)g/√3d)g/√5Correct answer is option 'C'. Can you explain this answer? covers all topics & solutions for NEET 2024 Exam.
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A triangular block of mass M with angles 30°, 60° and 90° rest with its 30° - 90° side on a horizontal table. A cubical block of mass m rests on 60° - 30° side. The acceleration which M must have relative to the table to keep m stationary relative to the triangular block is (assuming frictionless contact)a)gb)g/√2c)g/√3d)g/√5Correct answer is option 'C'. Can you explain this answer?, a detailed solution for A triangular block of mass M with angles 30°, 60° and 90° rest with its 30° - 90° side on a horizontal table. A cubical block of mass m rests on 60° - 30° side. The acceleration which M must have relative to the table to keep m stationary relative to the triangular block is (assuming frictionless contact)a)gb)g/√2c)g/√3d)g/√5Correct answer is option 'C'. Can you explain this answer? has been provided alongside types of A triangular block of mass M with angles 30°, 60° and 90° rest with its 30° - 90° side on a horizontal table. A cubical block of mass m rests on 60° - 30° side. The acceleration which M must have relative to the table to keep m stationary relative to the triangular block is (assuming frictionless contact)a)gb)g/√2c)g/√3d)g/√5Correct answer is option 'C'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice A triangular block of mass M with angles 30°, 60° and 90° rest with its 30° - 90° side on a horizontal table. A cubical block of mass m rests on 60° - 30° side. The acceleration which M must have relative to the table to keep m stationary relative to the triangular block is (assuming frictionless contact)a)gb)g/√2c)g/√3d)g/√5Correct answer is option 'C'. Can you explain this answer? tests, examples and also practice NEET tests.