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A ball of mass 3kg moving speed of 100m/s,strike a wall at an angle 60 Degree .The ball rebounds at the same speed and remains in contact with the ball for 0.2s,the force exerted by the ball on the wall is 1)1500root3N 2)1500N 3)300root3N 4)300N?
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A ball of mass 3kg moving speed of 100m/s,strike a wall at an angle 60...
Given:
Mass of ball (m) = 3kg
Initial velocity (u) = 100m/s
Angle of incidence (θ) = 60°
Time of contact (t) = 0.2s
To find:
The force exerted by the ball on the wall.
Solution:
1. Calculation of initial horizontal and vertical velocities:
Initial horizontal velocity (ux) = u cos θ
ux = 100 cos 60°
ux = 50m/s
Initial vertical velocity (uy) = u sin θ
uy = 100 sin 60°
uy = 86.6m/s
2. Calculation of final horizontal and vertical velocities:
As the ball rebounds with the same speed, the magnitude of the final velocity remains the same. However, the direction of the velocity changes. The vertical component of velocity changes direction due to the collision with the wall. Therefore, the final velocity can be calculated as follows:
Final horizontal velocity (vx) = ux
vx = 50m/s
Final vertical velocity (vy) = -uy
vy = -86.6m/s
3. Calculation of acceleration:
The acceleration due to gravity (g) acts in the vertical direction. Therefore, the acceleration can be calculated as follows:
a = g
a = 9.8m/s^2
4. Calculation of time of flight:
The time of flight (T) can be calculated using the following formula:
T = 2 * (uy / a)
T = 2 * (86.6 / 9.8)
T = 17.6s
5. Calculation of the height reached by the ball:
The maximum height reached by the ball (H) can be calculated using the following formula:
H = (uy^2) / (2 * a)
H = (86.6^2) / (2 * 9.8)
H = 384.5m
6. Calculation of force exerted by the ball on the wall:
The force exerted by the ball on the wall can be calculated using the following formula:
F = (2 * m * uy) / t
F = (2 * 3 * 86.6) / 0.2
F = 2598N
7. Calculation of horizontal and vertical components of force:
The horizontal and vertical components of force can be calculated as follows:
Horizontal component of force (Fx) = F * cos θ
Fx = 2598 * cos 60°
Fx = 1299N
Vertical component of force (Fy) = F * sin θ
Fy = 2598 * sin 60°
Fy = 2247N
Answer:
The force exerted by the ball on the wall is 2598N. The horizontal component of the force is 1299N, and the vertical component of the force is 2247N. Therefore, the correct option is 2) 1500N.
Mass of ball (m) = 3kg
Initial velocity (u) = 100m/s
Angle of incidence (θ) = 60°
Time of contact (t) = 0.2s
To find:
The force exerted by the ball on the wall.
Solution:
1. Calculation of initial horizontal and vertical velocities:
Initial horizontal velocity (ux) = u cos θ
ux = 100 cos 60°
ux = 50m/s
Initial vertical velocity (uy) = u sin θ
uy = 100 sin 60°
uy = 86.6m/s
2. Calculation of final horizontal and vertical velocities:
As the ball rebounds with the same speed, the magnitude of the final velocity remains the same. However, the direction of the velocity changes. The vertical component of velocity changes direction due to the collision with the wall. Therefore, the final velocity can be calculated as follows:
Final horizontal velocity (vx) = ux
vx = 50m/s
Final vertical velocity (vy) = -uy
vy = -86.6m/s
3. Calculation of acceleration:
The acceleration due to gravity (g) acts in the vertical direction. Therefore, the acceleration can be calculated as follows:
a = g
a = 9.8m/s^2
4. Calculation of time of flight:
The time of flight (T) can be calculated using the following formula:
T = 2 * (uy / a)
T = 2 * (86.6 / 9.8)
T = 17.6s
5. Calculation of the height reached by the ball:
The maximum height reached by the ball (H) can be calculated using the following formula:
H = (uy^2) / (2 * a)
H = (86.6^2) / (2 * 9.8)
H = 384.5m
6. Calculation of force exerted by the ball on the wall:
The force exerted by the ball on the wall can be calculated using the following formula:
F = (2 * m * uy) / t
F = (2 * 3 * 86.6) / 0.2
F = 2598N
7. Calculation of horizontal and vertical components of force:
The horizontal and vertical components of force can be calculated as follows:
Horizontal component of force (Fx) = F * cos θ
Fx = 2598 * cos 60°
Fx = 1299N
Vertical component of force (Fy) = F * sin θ
Fy = 2598 * sin 60°
Fy = 2247N
Answer:
The force exerted by the ball on the wall is 2598N. The horizontal component of the force is 1299N, and the vertical component of the force is 2247N. Therefore, the correct option is 2) 1500N.
Community Answer
A ball of mass 3kg moving speed of 100m/s,strike a wall at an angle 60...
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A ball of mass 3kg moving speed of 100m/s,strike a wall at an angle 60 Degree .The ball rebounds at the same speed and remains in contact with the ball for 0.2s,the force exerted by the ball on the wall is 1)1500root3N 2)1500N 3)300root3N 4)300N?
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A ball of mass 3kg moving speed of 100m/s,strike a wall at an angle 60 Degree .The ball rebounds at the same speed and remains in contact with the ball for 0.2s,the force exerted by the ball on the wall is 1)1500root3N 2)1500N 3)300root3N 4)300N? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about A ball of mass 3kg moving speed of 100m/s,strike a wall at an angle 60 Degree .The ball rebounds at the same speed and remains in contact with the ball for 0.2s,the force exerted by the ball on the wall is 1)1500root3N 2)1500N 3)300root3N 4)300N? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A ball of mass 3kg moving speed of 100m/s,strike a wall at an angle 60 Degree .The ball rebounds at the same speed and remains in contact with the ball for 0.2s,the force exerted by the ball on the wall is 1)1500root3N 2)1500N 3)300root3N 4)300N?.
A ball of mass 3kg moving speed of 100m/s,strike a wall at an angle 60 Degree .The ball rebounds at the same speed and remains in contact with the ball for 0.2s,the force exerted by the ball on the wall is 1)1500root3N 2)1500N 3)300root3N 4)300N? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about A ball of mass 3kg moving speed of 100m/s,strike a wall at an angle 60 Degree .The ball rebounds at the same speed and remains in contact with the ball for 0.2s,the force exerted by the ball on the wall is 1)1500root3N 2)1500N 3)300root3N 4)300N? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A ball of mass 3kg moving speed of 100m/s,strike a wall at an angle 60 Degree .The ball rebounds at the same speed and remains in contact with the ball for 0.2s,the force exerted by the ball on the wall is 1)1500root3N 2)1500N 3)300root3N 4)300N?.
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