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If at 298 K the bond energies of C – H, C – C, C = C and H – H bonds are 414 kJ mol–1, 347 kJ mol–1, 615 kJ mol-1 and 435 kJ mol–1 respectively, the value of enthalpy change for the reactionH2C = CH2(g) + H2(g) → H3C – CH3 (g)at 298 K will bea)+250 kJb)–250 kJc)+125 kJd)–125 kJCorrect answer is option 'D'. Can you explain this answer? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about If at 298 K the bond energies of C – H, C – C, C = C and H – H bonds are 414 kJ mol–1, 347 kJ mol–1, 615 kJ mol-1 and 435 kJ mol–1 respectively, the value of enthalpy change for the reactionH2C = CH2(g) + H2(g) → H3C – CH3 (g)at 298 K will bea)+250 kJb)–250 kJc)+125 kJd)–125 kJCorrect answer is option 'D'. Can you explain this answer? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for If at 298 K the bond energies of C – H, C – C, C = C and H – H bonds are 414 kJ mol–1, 347 kJ mol–1, 615 kJ mol-1 and 435 kJ mol–1 respectively, the value of enthalpy change for the reactionH2C = CH2(g) + H2(g) → H3C – CH3 (g)at 298 K will bea)+250 kJb)–250 kJc)+125 kJd)–125 kJCorrect answer is option 'D'. Can you explain this answer?.

Solutions for If at 298 K the bond energies of C – H, C – C, C = C and H – H bonds are 414 kJ mol–1, 347 kJ mol–1, 615 kJ mol-1 and 435 kJ mol–1 respectively, the value of enthalpy change for the reactionH2C = CH2(g) + H2(g) → H3C – CH3 (g)at 298 K will bea)+250 kJb)–250 kJc)+125 kJd)–125 kJCorrect answer is option 'D'. Can you explain this answer? in English & in Hindi are available as part of our courses for NEET. Download more important topics, notes, lectures and mock test series for NEET Exam by signing up for free.

Here you can find the meaning of If at 298 K the bond energies of C – H, C – C, C = C and H – H bonds are 414 kJ mol–1, 347 kJ mol–1, 615 kJ mol-1 and 435 kJ mol–1 respectively, the value of enthalpy change for the reactionH2C = CH2(g) + H2(g) → H3C – CH3 (g)at 298 K will bea)+250 kJb)–250 kJc)+125 kJd)–125 kJCorrect answer is option 'D'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of If at 298 K the bond energies of C – H, C – C, C = C and H – H bonds are 414 kJ mol–1, 347 kJ mol–1, 615 kJ mol-1 and 435 kJ mol–1 respectively, the value of enthalpy change for the reactionH2C = CH2(g) + H2(g) → H3C – CH3 (g)at 298 K will bea)+250 kJb)–250 kJc)+125 kJd)–125 kJCorrect answer is option 'D'. Can you explain this answer?, a detailed solution for If at 298 K the bond energies of C – H, C – C, C = C and H – H bonds are 414 kJ mol–1, 347 kJ mol–1, 615 kJ mol-1 and 435 kJ mol–1 respectively, the value of enthalpy change for the reactionH2C = CH2(g) + H2(g) → H3C – CH3 (g)at 298 K will bea)+250 kJb)–250 kJc)+125 kJd)–125 kJCorrect answer is option 'D'. Can you explain this answer? has been provided alongside types of If at 298 K the bond energies of C – H, C – C, C = C and H – H bonds are 414 kJ mol–1, 347 kJ mol–1, 615 kJ mol-1 and 435 kJ mol–1 respectively, the value of enthalpy change for the reactionH2C = CH2(g) + H2(g) → H3C – CH3 (g)at 298 K will bea)+250 kJb)–250 kJc)+125 kJd)–125 kJCorrect answer is option 'D'. Can you explain this answer? theory, EduRev gives you an ample number of questions to practice If at 298 K the bond energies of C – H, C – C, C = C and H – H bonds are 414 kJ mol–1, 347 kJ mol–1, 615 kJ mol-1 and 435 kJ mol–1 respectively, the value of enthalpy change for the reactionH2C = CH2(g) + H2(g) → H3C – CH3 (g)at 298 K will bea)+250 kJb)–250 kJc)+125 kJd)–125 kJCorrect answer is option 'D'. Can you explain this answer? tests, examples and also practice NEET tests.