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The radius of gyration of a uniform rod of length L about on axis passing through its centre of mass is
  • a)
    L/√12
  • b)
    L2/12
  • c)
    L/√3
  • d)
    L/√2
Correct answer is option 'A'. Can you explain this answer?
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The correct answer is b) L/√12

The radius of gyration (k) is given by the formula: k = √(I/m), where I is the moment of inertia and m is the mass.

For a uniform rod of length L, the moment of inertia about an axis passing through its center of mass is given by: I = (1/12)mL^2, where m is the mass of the rod.

Therefore, k = √((1/12)mL^2 / m) = √(L^2 / 12) = L/√12.
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The radius of gyration of a uniform rod of length L about on axis passing through its centre of mass isa)L/√12b)L2/12c)L/√3d)L/√2Correct answer is option 'A'. Can you explain this answer?
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