Assertion: stannous chloride is a powerful oxidising agent which oxidi...
Stannous chloride is strong reducing agent and not oxidizing agent so it reduce mercuric chloride to Mercury to form grey precipitate
Assertion: stannous chloride is a powerful oxidising agent which oxidi...
Introduction:
Stannous chloride (SnCl2) is a chemical compound that is commonly used in various industrial applications, including as a reducing agent and a catalyst. It is also known for its oxidizing properties, although it is not typically considered a powerful oxidizing agent. However, under certain conditions, stannous chloride can oxidize mercuric chloride (HgCl2) to elemental mercury (Hg).
Explanation:
Stannous chloride as a reducing agent:
1. Stannous chloride is commonly used as a reducing agent in various chemical reactions. It can donate electrons to other substances, thereby reducing their oxidation state. In this capacity, stannous chloride is often employed in the reduction of metal ions to their elemental form.
Stannous chloride and mercuric chloride:
1. Mercuric chloride (HgCl2) is a compound that contains mercury in its highest oxidation state (+2). It is typically a white solid that is highly toxic.
2. Stannous chloride can react with mercuric chloride in an oxidation-reduction reaction. The stannous chloride acts as a reducing agent, while mercuric chloride acts as an oxidizing agent.
3. In this reaction, stannous chloride donates electrons to mercuric chloride, causing the mercury atom to undergo a reduction in oxidation state from +2 to 0, resulting in the formation of elemental mercury.
4. The reaction can be represented by the following equation:
SnCl2 + 2HgCl2 → SnCl4 + 2Hg
Conditions for the reaction:
1. The oxidation of mercuric chloride by stannous chloride to elemental mercury is typically carried out in an acidic solution.
2. The presence of acid helps in the formation of tin(IV) chloride (SnCl4) as a byproduct and facilitates the overall reaction.
Visualization:
- Stannous chloride (SnCl2) donates electrons to mercuric chloride (HgCl2).
- The mercury atom in mercuric chloride undergoes a reduction in oxidation state from +2 to 0.
- As a result, elemental mercury (Hg) is formed.
- The reaction requires an acidic solution for optimal conditions and the formation of tin(IV) chloride as a byproduct.
Conclusion:
Stannous chloride can act as a reducing agent and oxidize mercuric chloride to elemental mercury under certain conditions. While stannous chloride is not typically considered a powerful oxidizing agent, it can facilitate the reduction of mercuric chloride to mercury in the presence of acid. This reaction is often used in various chemical processes and should be handled with caution due to the toxicity of mercury and the corrosive nature of stannous chloride.
To make sure you are not studying endlessly, EduRev has designed NEET study material, with Structured Courses, Videos, & Test Series. Plus get personalized analysis, doubt solving and improvement plans to achieve a great score in NEET.