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Two cells A and B are connected in the secondary circuit of a potentiometer one at a time and the balancing length are respectively 400cm and 440cm. The e.m.f of the cell A is 1.08 volt. The e.m.f of the second cell B in volts is
  • a)
    1.08
  • b)
    1.188
  • c)
    11.88
  • d)
    12.8
Correct answer is option 'B'. Can you explain this answer?
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Given data:
- Balancing length for cell A = 400 cm
- Balancing length for cell B = 440 cm
- E.m.f of cell A = 1.08 V

Calculation:
- Let the e.m.f of cell B be E volts
- According to the principle of potentiometer,
E.m.f of cell A / Balancing length for cell A = E.m.f of cell B / Balancing length for cell B
- 1.08 / 400 = E / 440
- E = (1.08 * 440) / 400
- E = 1.188 V

Therefore, the e.m.f of the second cell B is 1.188 volts. Hence, the correct answer is option 'B'.
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Two cells A and B are connected in the secondary circuit of a potentiometer one at a time and the balancing length are respectively 400cm and 440cm. The e.m.f of the cell A is 1.08 volt. The e.m.f of the second cell B in volts isa) 1.08 b) 1.188 c) 11.88 d) 12.8 Correct answer is option 'B'. Can you explain this answer?
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Two cells A and B are connected in the secondary circuit of a potentiometer one at a time and the balancing length are respectively 400cm and 440cm. The e.m.f of the cell A is 1.08 volt. The e.m.f of the second cell B in volts isa) 1.08 b) 1.188 c) 11.88 d) 12.8 Correct answer is option 'B'. Can you explain this answer? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about Two cells A and B are connected in the secondary circuit of a potentiometer one at a time and the balancing length are respectively 400cm and 440cm. The e.m.f of the cell A is 1.08 volt. The e.m.f of the second cell B in volts isa) 1.08 b) 1.188 c) 11.88 d) 12.8 Correct answer is option 'B'. Can you explain this answer? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Two cells A and B are connected in the secondary circuit of a potentiometer one at a time and the balancing length are respectively 400cm and 440cm. The e.m.f of the cell A is 1.08 volt. The e.m.f of the second cell B in volts isa) 1.08 b) 1.188 c) 11.88 d) 12.8 Correct answer is option 'B'. Can you explain this answer?.
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