NEET Exam > NEET Questions > In a potentiometer experiment the balancing ...
Start Learning for Free
In a potentiometer experiment the balancing length of the cell was found to be 80 cm. Now, a resistance of 8 Ω is connected across the terminal of this cell the balancing length becomes 60 cm. The internal resistance of this cell is
- a)8/3 Ω
- b)4/3 Ω
- c)2 Ω
- d)3 Ω
Correct answer is option 'A'. Can you explain this answer?
| FREE This question is part of | Download PDF Attempt this Test |
Most Upvoted Answer
In a potentiometer experiment the balancing length of the cell was fo...
Free Test
FREE
| Start Free Test |
Community Answer
In a potentiometer experiment the balancing length of the cell was fo...
Balancing Length in Potentiometer Experiment:
In a potentiometer experiment, the balancing length is the position along the wire where the potential difference is zero. It is used to determine the unknown emf or internal resistance of a cell.
Given Information:
- Balancing length without any external resistance connected: 80 cm
- Balancing length with a resistance of 8 Ω connected: 60 cm
Determination of Internal Resistance:
We can use the concept of potential drop in a potentiometer wire to determine the internal resistance of the cell.
1. Potential drop across the wire without any external resistance:
The potential drop across the wire is directly proportional to the length of the wire. Therefore, the potential drop across the balancing length (80 cm) is equal to the emf of the cell.
2. Potential drop across the wire with an external resistance of 8 Ω:
When the external resistance (8 Ω) is connected, the potential drop across the wire decreases. The new potential drop is equal to the emf minus the potential drop across the internal resistance.
Using the formula: V = IR
- Potential drop across the wire without any external resistance: V1 = emf
- Potential drop across the wire with an external resistance: V2 = emf - (8 Ω) * I
where I is the current flowing through the circuit.
3. Determination of the internal resistance:
Since the balancing length decreases from 80 cm to 60 cm, the potential drop across the wire decreases. Therefore, we can equate the potential drops in the two cases:
V1 = V2
emf = emf - (8 Ω) * I
Simplifying the equation:
(8 Ω) * I = 0
I = 0
This implies that when the balancing length is 60 cm, no current is flowing through the circuit.
4. Calculation of internal resistance:
Using Ohm's Law: emf = (internal resistance) * I
Since I = 0 in this case, the internal resistance of the cell is equal to the external resistance connected across the terminal, which is 8 Ω.
Therefore, the correct answer is option 'A': 8/3 Ω.
In a potentiometer experiment, the balancing length is the position along the wire where the potential difference is zero. It is used to determine the unknown emf or internal resistance of a cell.
Given Information:
- Balancing length without any external resistance connected: 80 cm
- Balancing length with a resistance of 8 Ω connected: 60 cm
Determination of Internal Resistance:
We can use the concept of potential drop in a potentiometer wire to determine the internal resistance of the cell.
1. Potential drop across the wire without any external resistance:
The potential drop across the wire is directly proportional to the length of the wire. Therefore, the potential drop across the balancing length (80 cm) is equal to the emf of the cell.
2. Potential drop across the wire with an external resistance of 8 Ω:
When the external resistance (8 Ω) is connected, the potential drop across the wire decreases. The new potential drop is equal to the emf minus the potential drop across the internal resistance.
Using the formula: V = IR
- Potential drop across the wire without any external resistance: V1 = emf
- Potential drop across the wire with an external resistance: V2 = emf - (8 Ω) * I
where I is the current flowing through the circuit.
3. Determination of the internal resistance:
Since the balancing length decreases from 80 cm to 60 cm, the potential drop across the wire decreases. Therefore, we can equate the potential drops in the two cases:
V1 = V2
emf = emf - (8 Ω) * I
Simplifying the equation:
(8 Ω) * I = 0
I = 0
This implies that when the balancing length is 60 cm, no current is flowing through the circuit.
4. Calculation of internal resistance:
Using Ohm's Law: emf = (internal resistance) * I
Since I = 0 in this case, the internal resistance of the cell is equal to the external resistance connected across the terminal, which is 8 Ω.
Therefore, the correct answer is option 'A': 8/3 Ω.
Attention NEET Students!
To make sure you are not studying endlessly, EduRev has designed NEET study material, with Structured Courses, Videos, & Test Series. Plus get personalized analysis, doubt solving and improvement plans to achieve a great score in NEET.
|
Explore Courses for NEET exam
|
|
Similar NEET Doubts
Top Courses for NEETView all
In a potentiometer experiment the balancing length of the cell was found to be 80 cm. Now, a resistance of 8 Ω is connected across the terminal of this cell the balancing length becomes 60 cm. The internal resistance of this cell isa)8/3 Ωb)4/3 Ωc)2 Ωd)3 ΩCorrect answer is option 'A'. Can you explain this answer?
Question Description
In a potentiometer experiment the balancing length of the cell was found to be 80 cm. Now, a resistance of 8 Ω is connected across the terminal of this cell the balancing length becomes 60 cm. The internal resistance of this cell isa)8/3 Ωb)4/3 Ωc)2 Ωd)3 ΩCorrect answer is option 'A'. Can you explain this answer? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about In a potentiometer experiment the balancing length of the cell was found to be 80 cm. Now, a resistance of 8 Ω is connected across the terminal of this cell the balancing length becomes 60 cm. The internal resistance of this cell isa)8/3 Ωb)4/3 Ωc)2 Ωd)3 ΩCorrect answer is option 'A'. Can you explain this answer? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for In a potentiometer experiment the balancing length of the cell was found to be 80 cm. Now, a resistance of 8 Ω is connected across the terminal of this cell the balancing length becomes 60 cm. The internal resistance of this cell isa)8/3 Ωb)4/3 Ωc)2 Ωd)3 ΩCorrect answer is option 'A'. Can you explain this answer?.
In a potentiometer experiment the balancing length of the cell was found to be 80 cm. Now, a resistance of 8 Ω is connected across the terminal of this cell the balancing length becomes 60 cm. The internal resistance of this cell isa)8/3 Ωb)4/3 Ωc)2 Ωd)3 ΩCorrect answer is option 'A'. Can you explain this answer? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about In a potentiometer experiment the balancing length of the cell was found to be 80 cm. Now, a resistance of 8 Ω is connected across the terminal of this cell the balancing length becomes 60 cm. The internal resistance of this cell isa)8/3 Ωb)4/3 Ωc)2 Ωd)3 ΩCorrect answer is option 'A'. Can you explain this answer? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for In a potentiometer experiment the balancing length of the cell was found to be 80 cm. Now, a resistance of 8 Ω is connected across the terminal of this cell the balancing length becomes 60 cm. The internal resistance of this cell isa)8/3 Ωb)4/3 Ωc)2 Ωd)3 ΩCorrect answer is option 'A'. Can you explain this answer?.
Solutions for In a potentiometer experiment the balancing length of the cell was found to be 80 cm. Now, a resistance of 8 Ω is connected across the terminal of this cell the balancing length becomes 60 cm. The internal resistance of this cell isa)8/3 Ωb)4/3 Ωc)2 Ωd)3 ΩCorrect answer is option 'A'. Can you explain this answer? in English & in Hindi are available as part of our courses for NEET.
Download more important topics, notes, lectures and mock test series for NEET Exam by signing up for free.
Here you can find the meaning of In a potentiometer experiment the balancing length of the cell was found to be 80 cm. Now, a resistance of 8 Ω is connected across the terminal of this cell the balancing length becomes 60 cm. The internal resistance of this cell isa)8/3 Ωb)4/3 Ωc)2 Ωd)3 ΩCorrect answer is option 'A'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of
In a potentiometer experiment the balancing length of the cell was found to be 80 cm. Now, a resistance of 8 Ω is connected across the terminal of this cell the balancing length becomes 60 cm. The internal resistance of this cell isa)8/3 Ωb)4/3 Ωc)2 Ωd)3 ΩCorrect answer is option 'A'. Can you explain this answer?, a detailed solution for In a potentiometer experiment the balancing length of the cell was found to be 80 cm. Now, a resistance of 8 Ω is connected across the terminal of this cell the balancing length becomes 60 cm. The internal resistance of this cell isa)8/3 Ωb)4/3 Ωc)2 Ωd)3 ΩCorrect answer is option 'A'. Can you explain this answer? has been provided alongside types of In a potentiometer experiment the balancing length of the cell was found to be 80 cm. Now, a resistance of 8 Ω is connected across the terminal of this cell the balancing length becomes 60 cm. The internal resistance of this cell isa)8/3 Ωb)4/3 Ωc)2 Ωd)3 ΩCorrect answer is option 'A'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice In a potentiometer experiment the balancing length of the cell was found to be 80 cm. Now, a resistance of 8 Ω is connected across the terminal of this cell the balancing length becomes 60 cm. The internal resistance of this cell isa)8/3 Ωb)4/3 Ωc)2 Ωd)3 ΩCorrect answer is option 'A'. Can you explain this answer? tests, examples and also practice NEET tests.
|
|
Explore Courses for NEET exam
|
|
Suggested Free Tests
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
|
© EduRev
|
Education Revolution
|
Follow Us
|
Signup to see your scores
go up within 7 days!
Access 1000+ FREE Docs, Videos and Tests
Takes less than 10 seconds to signup