A is twice as good a workman as B and together they finish a piece of ...
If time taken by B be 2x days then time taken by A = x days.
∴ 1/x+1/2x = 1/14
=2+1/2x = 1/14
= 3x = 1/7
= x = 1/ 3 ×7 = 1/21
= 21 days
A is twice as good a workman as B and together they finish a piece of ...
Given: A is twice as good a workman as B
Together they finish a piece of work in 14 days
To Find:
A alone can finish the work in how many days.
Solution:
Let's assume that B alone can finish the work in 'x' days.
So, A alone can finish the work in 'x/2' days. (As given, A is twice as good a workman as B)
As per the given condition, A and B together can finish the work in 14 days.
So, we can write the below equation based on work done by A and B together in 1 day.
Work done by A and B together in 1 day = 1/14
Now, let's calculate work done by A and B separately in 1 day.
Work done by A in 1 day = 1/(x/2) = 2/x
Work done by B in 1 day = 1/x
Total work done by A and B together in 1 day = Work done by A in 1 day + Work done by B in 1 day
1/14 = 2/x + 1/x
1/14 = 3/x
x = 42
Therefore, B alone can finish the work in 42 days.
And A can finish the work in x/2 = 21 days.
Hence, the correct answer is option (b) 21 days.