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A vehicle of mass m is moving on a rough horizontal road with momentum P. If the coefficient of friction between the tyres and the road be μ, then the stopping distance is
- a)P/2μm g
- b)p2/2μm g
- c)P/2μm2g
- d)p2/2μm2g
Correct answer is option 'D'. Can you explain this answer?
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Μ, then the force of friction acting on the vehicle is given by:
Ffriction = μmg
where g is the acceleration due to gravity.
The force of friction acts in the opposite direction to the motion of the vehicle, which means that it will cause a deceleration of the vehicle. The deceleration, a, is given by:
a = Ffriction/m = μg
The time taken, t, for the vehicle to come to rest is given by:
t = P/Ffriction = P/(μmg)
Substituting the value of Ffriction in terms of μ and solving for t, we get:
t = P/(μmg) = P/(μm*g) = P/(μ*9.8*m)
Therefore, the time taken for the vehicle to come to rest depends on the momentum of the vehicle and the coefficient of friction between the tyres and the road. The greater the momentum of the vehicle, the longer it will take to come to rest, and the greater the coefficient of friction, the shorter it will take to come to rest.
Ffriction = μmg
where g is the acceleration due to gravity.
The force of friction acts in the opposite direction to the motion of the vehicle, which means that it will cause a deceleration of the vehicle. The deceleration, a, is given by:
a = Ffriction/m = μg
The time taken, t, for the vehicle to come to rest is given by:
t = P/Ffriction = P/(μmg)
Substituting the value of Ffriction in terms of μ and solving for t, we get:
t = P/(μmg) = P/(μm*g) = P/(μ*9.8*m)
Therefore, the time taken for the vehicle to come to rest depends on the momentum of the vehicle and the coefficient of friction between the tyres and the road. The greater the momentum of the vehicle, the longer it will take to come to rest, and the greater the coefficient of friction, the shorter it will take to come to rest.
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A vehicle of mass m is moving on a rough horizontal road with momentum P. If the coefficient of friction between the tyres and the road be μ, then the stopping distance isa)P/2μm gb)p2/2μm gc)P/2μm2gd)p2/2μm2gCorrect answer is option 'D'. Can you explain this answer?
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A vehicle of mass m is moving on a rough horizontal road with momentum P. If the coefficient of friction between the tyres and the road be μ, then the stopping distance isa)P/2μm gb)p2/2μm gc)P/2μm2gd)p2/2μm2gCorrect answer is option 'D'. Can you explain this answer? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about A vehicle of mass m is moving on a rough horizontal road with momentum P. If the coefficient of friction between the tyres and the road be μ, then the stopping distance isa)P/2μm gb)p2/2μm gc)P/2μm2gd)p2/2μm2gCorrect answer is option 'D'. Can you explain this answer? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A vehicle of mass m is moving on a rough horizontal road with momentum P. If the coefficient of friction between the tyres and the road be μ, then the stopping distance isa)P/2μm gb)p2/2μm gc)P/2μm2gd)p2/2μm2gCorrect answer is option 'D'. Can you explain this answer?.
A vehicle of mass m is moving on a rough horizontal road with momentum P. If the coefficient of friction between the tyres and the road be μ, then the stopping distance isa)P/2μm gb)p2/2μm gc)P/2μm2gd)p2/2μm2gCorrect answer is option 'D'. Can you explain this answer? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about A vehicle of mass m is moving on a rough horizontal road with momentum P. If the coefficient of friction between the tyres and the road be μ, then the stopping distance isa)P/2μm gb)p2/2μm gc)P/2μm2gd)p2/2μm2gCorrect answer is option 'D'. Can you explain this answer? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A vehicle of mass m is moving on a rough horizontal road with momentum P. If the coefficient of friction between the tyres and the road be μ, then the stopping distance isa)P/2μm gb)p2/2μm gc)P/2μm2gd)p2/2μm2gCorrect answer is option 'D'. Can you explain this answer?.
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