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20ml of a water sample required 2.94 mg of K2Cr2O7 (molar mass = 294 g) for the oxidation of dissolved organic matter. The C.O.D. of water sample is?
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20ml of a water sample required 2.94 mg of K2Cr2O7 (molar mass = 294 g...
COD Calculation
1. Introduction:
COD stands for Chemical Oxygen Demand. It is a measure of the amount of organic compounds present in water that can be oxidized by a strong oxidizing agent. In this case, we are using K2Cr2O7 as the oxidizing agent.
2. Given Information:
- Volume of water sample = 20 ml
- Amount of K2Cr2O7 required = 2.94 mg
- Molar mass of K2Cr2O7 = 294 g/mol
3. Calculation of moles of K2Cr2O7:
To calculate the moles of K2Cr2O7, we need to use the formula:
Moles = Mass / Molar Mass
Given that the mass of K2Cr2O7 is 2.94 mg and the molar mass is 294 g/mol, we can convert the mass to grams:
Mass of K2Cr2O7 = 2.94 mg = 0.00294 g
Now, we can calculate the moles of K2Cr2O7:
Moles of K2Cr2O7 = 0.00294 g / 294 g/mol = 0.00001 mol
4. Calculation of moles of organic matter:
Since the K2Cr2O7 is used to oxidize the organic matter present in the water sample, the moles of organic matter can be determined by stoichiometry. The balanced equation for the reaction is:
3C + K2Cr2O7 + 4H2SO4 → 3CO2 + Cr2(SO4)3 + K2SO4 + 4H2O
From the balanced equation, we can see that 1 mol of K2Cr2O7 reacts with 3 moles of organic matter (C). Therefore, the moles of organic matter can be calculated as:
Moles of organic matter = 0.00001 mol × 3 = 0.00003 mol
5. Calculation of COD:
COD is defined as the amount of oxygen required to oxidize the organic matter in water. From the balanced equation, we can see that 1 mole of organic matter requires 3 moles of oxygen for complete oxidation. Therefore, the moles of oxygen required can be calculated as:
Moles of oxygen = 0.00003 mol × 3 = 0.00009 mol
Since the volume of water sample is 20 ml, the concentration of COD can be calculated as:
COD = Moles of oxygen / Volume of water sample
COD = 0.00009 mol / 0.02 L = 0.0045 mol/L
6. Conclusion:
The COD of the water sample is 0.0045 mol/L. This means that the water sample contains 0.0045 moles of organic matter per liter of water, which can be oxidized by the K2Cr2O7 solution. COD is an important parameter for assessing the quality of water, as it indicates the level of organic pollution present.
1. Introduction:
COD stands for Chemical Oxygen Demand. It is a measure of the amount of organic compounds present in water that can be oxidized by a strong oxidizing agent. In this case, we are using K2Cr2O7 as the oxidizing agent.
2. Given Information:
- Volume of water sample = 20 ml
- Amount of K2Cr2O7 required = 2.94 mg
- Molar mass of K2Cr2O7 = 294 g/mol
3. Calculation of moles of K2Cr2O7:
To calculate the moles of K2Cr2O7, we need to use the formula:
Moles = Mass / Molar Mass
Given that the mass of K2Cr2O7 is 2.94 mg and the molar mass is 294 g/mol, we can convert the mass to grams:
Mass of K2Cr2O7 = 2.94 mg = 0.00294 g
Now, we can calculate the moles of K2Cr2O7:
Moles of K2Cr2O7 = 0.00294 g / 294 g/mol = 0.00001 mol
4. Calculation of moles of organic matter:
Since the K2Cr2O7 is used to oxidize the organic matter present in the water sample, the moles of organic matter can be determined by stoichiometry. The balanced equation for the reaction is:
3C + K2Cr2O7 + 4H2SO4 → 3CO2 + Cr2(SO4)3 + K2SO4 + 4H2O
From the balanced equation, we can see that 1 mol of K2Cr2O7 reacts with 3 moles of organic matter (C). Therefore, the moles of organic matter can be calculated as:
Moles of organic matter = 0.00001 mol × 3 = 0.00003 mol
5. Calculation of COD:
COD is defined as the amount of oxygen required to oxidize the organic matter in water. From the balanced equation, we can see that 1 mole of organic matter requires 3 moles of oxygen for complete oxidation. Therefore, the moles of oxygen required can be calculated as:
Moles of oxygen = 0.00003 mol × 3 = 0.00009 mol
Since the volume of water sample is 20 ml, the concentration of COD can be calculated as:
COD = Moles of oxygen / Volume of water sample
COD = 0.00009 mol / 0.02 L = 0.0045 mol/L
6. Conclusion:
The COD of the water sample is 0.0045 mol/L. This means that the water sample contains 0.0045 moles of organic matter per liter of water, which can be oxidized by the K2Cr2O7 solution. COD is an important parameter for assessing the quality of water, as it indicates the level of organic pollution present.
Community Answer
20ml of a water sample required 2.94 mg of K2Cr2O7 (molar mass = 294 g...
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20ml of a water sample required 2.94 mg of K2Cr2O7 (molar mass = 294 g) for the oxidation of dissolved organic matter. The C.O.D. of water sample is?
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20ml of a water sample required 2.94 mg of K2Cr2O7 (molar mass = 294 g) for the oxidation of dissolved organic matter. The C.O.D. of water sample is? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about 20ml of a water sample required 2.94 mg of K2Cr2O7 (molar mass = 294 g) for the oxidation of dissolved organic matter. The C.O.D. of water sample is? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for 20ml of a water sample required 2.94 mg of K2Cr2O7 (molar mass = 294 g) for the oxidation of dissolved organic matter. The C.O.D. of water sample is?.
20ml of a water sample required 2.94 mg of K2Cr2O7 (molar mass = 294 g) for the oxidation of dissolved organic matter. The C.O.D. of water sample is? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about 20ml of a water sample required 2.94 mg of K2Cr2O7 (molar mass = 294 g) for the oxidation of dissolved organic matter. The C.O.D. of water sample is? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for 20ml of a water sample required 2.94 mg of K2Cr2O7 (molar mass = 294 g) for the oxidation of dissolved organic matter. The C.O.D. of water sample is?.
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