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If the equation for the displacement of a particle moving on a circular path is given by (θ) = 2t3+ 0.5, where θ is in radians and t in seconds, then the angular velocity of the particle after 2 sec from its start isa)8 rad/secb)12 rad/secc)24 rad/secd)36 rad/secCorrect answer is option 'C'. Can you explain this answer? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared
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If the equation for the displacement of a particle moving on a circular path is given by (θ) = 2t3+ 0.5, where θ is in radians and t in seconds, then the angular velocity of the particle after 2 sec from its start isa)8 rad/secb)12 rad/secc)24 rad/secd)36 rad/secCorrect answer is option 'C'. Can you explain this answer?, a detailed solution for If the equation for the displacement of a particle moving on a circular path is given by (θ) = 2t3+ 0.5, where θ is in radians and t in seconds, then the angular velocity of the particle after 2 sec from its start isa)8 rad/secb)12 rad/secc)24 rad/secd)36 rad/secCorrect answer is option 'C'. Can you explain this answer? has been provided alongside types of If the equation for the displacement of a particle moving on a circular path is given by (θ) = 2t3+ 0.5, where θ is in radians and t in seconds, then the angular velocity of the particle after 2 sec from its start isa)8 rad/secb)12 rad/secc)24 rad/secd)36 rad/secCorrect answer is option 'C'. Can you explain this answer? theory, EduRev gives you an
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