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If the equation for the displacement of a particle moving on a circular path is given by (θ) = 2t3 + 0.5, where θ is in radians and t in seconds, then the angular velocity of the particle after 2 sec from its start is
  • a)
    8 rad/sec
  • b)
    12 rad/sec
  • c)
    24 rad/sec
  • d)
    36 rad/sec
Correct answer is option 'C'. Can you explain this answer?
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If the equation for the displacement of a particle moving on a circula...
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If the equation for the displacement of a particle moving on a circula...
Angular velocity = differentiation of angular displacement...by differentiation of given equation we get angular velocity as 6t^2.after.time t=2sec starting from rest ...angular velocity will be 24 rad/sec
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If the equation for the displacement of a particle moving on a circular path is given by (θ) = 2t3+ 0.5, where θ is in radians and t in seconds, then the angular velocity of the particle after 2 sec from its start isa)8 rad/secb)12 rad/secc)24 rad/secd)36 rad/secCorrect answer is option 'C'. Can you explain this answer?
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