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Two sphers of radii r1 and r2 having equal charges afe joined together with a copper wire . If v is the potential of each sphere after they are seprated from each other then the initial charg on both sphere was?
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Two sphers of radii r1 and r2 having equal charges afe joined together...
Given:

Two spheres of radii r1 and r2 having equal charges are joined together with a copper wire.

Let the potential of each sphere after they are separated be v.

To find:

The initial charge on both spheres.

Solution:

When two spheres are joined with a copper wire, they become equipotential. Therefore, the potential of each sphere will be the same, i.e., v.

Using the formula for potential:

V = kQ/r

where V is the potential, k is Coulomb's constant, Q is the charge on the sphere, and r is the radius of the sphere.

For sphere 1:

V = kQ1/r1

Q1 = Vr1/k

For sphere 2:

V = kQ2/r2

Q2 = Vr2/k

Since the spheres have equal charges, Q1 = Q2.

Therefore, Vr1/k = Vr2/k

r1/r2 = V/V

Since the radii are known, the ratio of charges can be found.

Q1/Q2 = (r1/r2)^2

Now, the problem can be solved by substituting the given values of r1, r2, and V.

Answer:

The initial charge on both spheres was Q1 = Q2 = Vr/k, where r is the radius of the spheres and k is Coulomb's constant.
Community Answer
Two sphers of radii r1 and r2 having equal charges afe joined together...
V=K(Q1 + Q2) ÷ (R1 + R2)

Q1= Q2

V = 2KQ ÷ (R1 + R2)

Q = V (R1 + R2) ÷ 2K
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Two sphers of radii r1 and r2 having equal charges afe joined together with a copper wire . If v is the potential of each sphere after they are seprated from each other then the initial charg on both sphere was?
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