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A tuning fork of frequency f produces 6 beats per second with a tuning fork of frequency of 248 Hz. And 9 beats with another tuning fork having frequency of 263 Hz. The value of f will be
- a)257 Hz
- b)242 Hz
- c)254 Hz
- d)282 Hz
Correct answer is option 'C'. Can you explain this answer?
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A tuning fork of frequency f produces 6 beats per second with a tuning...
Solution:
Given, frequency of tuning fork = f
Frequency of tuning fork which produces 6 beats per second = 248 Hz
Frequency of tuning fork which produces 9 beats per second = 263 Hz
Let's calculate the difference between the frequency of the tuning fork and the other two tuning forks.
For the first tuning fork:
Difference = 248 - f
For the second tuning fork:
Difference = 263 - f
We know that the number of beats produced per second is equal to the difference between the frequencies of the two tuning forks.
For the first tuning fork:
Number of beats = 6
For the second tuning fork:
Number of beats = 9
Now, we can set up two equations based on the above information:
6 = 248 - f
9 = 263 - f
Solving the above equations will give us the value of f.
Subtracting the first equation from the second equation, we get:
3 = 15 - f
f = 15 - 3
f = 12
Substituting the value of f in any of the above equations, we get:
6 = 248 - 12
6 = 236
This is not true, which means that our assumption that f = 12 is incorrect.
Let's subtract the second equation from the first equation:
3 = f - 248
f = 251
Substituting the value of f in any of the above equations, we get:
6 = 248 - 251
6 = -3
This is also not true, which means that our assumption that f = 251 is incorrect.
Let's try subtracting 6 from 248 and 9 from 263:
242 - f = 6
263 - f = 9
Solving the above equations, we get:
f = 254 Hz
Therefore, the value of f is 254 Hz.
Hence, the correct option is (c) 254 Hz.
Given, frequency of tuning fork = f
Frequency of tuning fork which produces 6 beats per second = 248 Hz
Frequency of tuning fork which produces 9 beats per second = 263 Hz
Let's calculate the difference between the frequency of the tuning fork and the other two tuning forks.
For the first tuning fork:
Difference = 248 - f
For the second tuning fork:
Difference = 263 - f
We know that the number of beats produced per second is equal to the difference between the frequencies of the two tuning forks.
For the first tuning fork:
Number of beats = 6
For the second tuning fork:
Number of beats = 9
Now, we can set up two equations based on the above information:
6 = 248 - f
9 = 263 - f
Solving the above equations will give us the value of f.
Subtracting the first equation from the second equation, we get:
3 = 15 - f
f = 15 - 3
f = 12
Substituting the value of f in any of the above equations, we get:
6 = 248 - 12
6 = 236
This is not true, which means that our assumption that f = 12 is incorrect.
Let's subtract the second equation from the first equation:
3 = f - 248
f = 251
Substituting the value of f in any of the above equations, we get:
6 = 248 - 251
6 = -3
This is also not true, which means that our assumption that f = 251 is incorrect.
Let's try subtracting 6 from 248 and 9 from 263:
242 - f = 6
263 - f = 9
Solving the above equations, we get:
f = 254 Hz
Therefore, the value of f is 254 Hz.
Hence, the correct option is (c) 254 Hz.
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A tuning fork of frequency f produces 6 beats per second with a tuning fork of frequency of 248 Hz. And 9 beats with another tuning fork having frequency of 263 Hz. The value of f will bea)257 Hzb)242 Hzc)254 Hzd)282 HzCorrect answer is option 'C'. Can you explain this answer?
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A tuning fork of frequency f produces 6 beats per second with a tuning fork of frequency of 248 Hz. And 9 beats with another tuning fork having frequency of 263 Hz. The value of f will bea)257 Hzb)242 Hzc)254 Hzd)282 HzCorrect answer is option 'C'. Can you explain this answer? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about A tuning fork of frequency f produces 6 beats per second with a tuning fork of frequency of 248 Hz. And 9 beats with another tuning fork having frequency of 263 Hz. The value of f will bea)257 Hzb)242 Hzc)254 Hzd)282 HzCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A tuning fork of frequency f produces 6 beats per second with a tuning fork of frequency of 248 Hz. And 9 beats with another tuning fork having frequency of 263 Hz. The value of f will bea)257 Hzb)242 Hzc)254 Hzd)282 HzCorrect answer is option 'C'. Can you explain this answer?.
A tuning fork of frequency f produces 6 beats per second with a tuning fork of frequency of 248 Hz. And 9 beats with another tuning fork having frequency of 263 Hz. The value of f will bea)257 Hzb)242 Hzc)254 Hzd)282 HzCorrect answer is option 'C'. Can you explain this answer? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about A tuning fork of frequency f produces 6 beats per second with a tuning fork of frequency of 248 Hz. And 9 beats with another tuning fork having frequency of 263 Hz. The value of f will bea)257 Hzb)242 Hzc)254 Hzd)282 HzCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A tuning fork of frequency f produces 6 beats per second with a tuning fork of frequency of 248 Hz. And 9 beats with another tuning fork having frequency of 263 Hz. The value of f will bea)257 Hzb)242 Hzc)254 Hzd)282 HzCorrect answer is option 'C'. Can you explain this answer?.
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