Is it 0.49 frequency or 49% ??...
Albino(q^2)=300/900...
q^2=1/3...
q=√(1/3)...
q=1/√3...
q=√3/3...
q=0.57...
we know that;
p+q=1..
p+0.57=1..
p=1-0.57..
p=0.43..
Now; in question its asked about frequency of carriers=2pq=2×0.57×0.43=0.49=49%......

Solution:

Population information:

Total population = 900
Albino population = 300

Frequency of Albino:

The frequency of Albino can be calculated using the following formula:

Frequency of Albino = (Number of Albino / Total Population)

Frequency of Albino = (300 / 900) = 1/3

Frequency of Carriers:

According to the Hardy-Weinberg principle, the frequency of carriers can be calculated using the following formula:

Frequency of Carriers = 2pq

Where,
p = frequency of dominant allele
q = frequency of recessive allele

Given that the frequency of Albino is 1/3, the frequency of the recessive allele (q) can be calculated as follows:

q = √(Frequency of Albino)

q = √(1/3) = 0.577

Since there are only two alleles in the population, the frequency of the dominant allele (p) can be calculated as:

p = 1 - q

p = 1 - 0.577 = 0.423

Using these values, the frequency of carriers can be calculated as:

Frequency of Carriers = 2pq = 2 x 0.423 x 0.577 = 0.489

Therefore, the frequency of carriers in the population is 0.489 or 48.9%.

Explanation of Hardy-Weinberg principle:

The Hardy-Weinberg principle is a mathematical model that describes the distribution of alleles in a population. It states that in a large, randomly mating population, the frequency of alleles will remain constant from generation to generation if the following conditions are met:

1. No mutations occur
2. No migration occurs
3. The population is large enough to prevent genetic drift
4. Mating is random
5. Natural selection does not occur

The Hardy-Weinberg principle can be used to calculate the frequency of alleles, genotypes, and phenotypes in a population. It is a useful tool for predicting how genetic traits will be distributed in future generations.