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In young's double slit experiment the y-coordinate of Central Maxima maxima and 10 th Maxima are 2 cm and 5 cm respectively . when the YDSE apparatus is immersed in a liquid of refractive index 1.5 .the corresponding y coordinates will be?
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In young's double slit experiment the y-coordinate of Central Maxima m...
Explanation:

  • In Young's double slit experiment, the distance between two slits is d.

  • The distance between the screen and the slits is D.

  • The distance between the central maximum and the nth maximum is given by the formula:

    yn = nλD/d

  • Here, y1 = 2 cm and y10 = 5 cm.

  • Let's find the value of λD/d using the above values.

  • λD/d = yn/n = y1/1 = 2 cm/1 = 2 cm.

  • Now, when the YDSE apparatus is immersed in a liquid of refractive index 1.5, the wavelength of light changes.

  • The new wavelength of light is given by the formula:

    λ' = λ/n, where n is the refractive index of the medium.

  • Here, λ' = λ/1.5.

  • Now, let's find the new y-coordinates of the central maximum and the 10th maximum.

  • The new value of y1' (central maximum) is given by the formula:

    y1' = λ'D'/d

  • Substituting the values, we get:

    y1' = (λ/1.5) x D/d = (2/3) x 2 cm = 4/3 cm.

  • Similarly, the new value of y10' is given by the formula:

    y10' = 10λ'D'/d

  • Substituting the values, we get:

    y10' = 10 x (λ/1.5) x D/d = (20/3) x 5 cm = 100/3 cm.



Therefore, the new y-coordinates of the central maximum and the 10th maximum are 4/3 cm and 100/3 cm respectively when the YDSE apparatus is immersed in a liquid of refractive index 1.5.
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In young's double slit experiment the y-coordinate of Central Maxima m...
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In young's double slit experiment the y-coordinate of Central Maxima maxima and 10 th Maxima are 2 cm and 5 cm respectively . when the YDSE apparatus is immersed in a liquid of refractive index 1.5 .the corresponding y coordinates will be?
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