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2n=16 is in primary spermatocyte which is in metaphase of first meiotic division who shall be the total number of chromatids in each of the secondary spermatocyte??? 1)16 2)32 3)24 4)8?
Most Upvoted Answer
2n=16 is in primary spermatocyte which is in metaphase of first meioti...
It's option A...as secondary spermatocyte is haploid i.e. ' n '...
given; 2n=16..
n=8...
1 chromosome = 2 chromatids..
Here; 2×8=16 chromatids..
Community Answer
2n=16 is in primary spermatocyte which is in metaphase of first meioti...
Explanation:

During meiosis, a diploid cell undergoes two rounds of cell division to produce four haploid cells. The first meiotic division separates homologous chromosomes, while the second meiotic division separates sister chromatids.

Calculating the Total Number of Chromatids:

- The given equation, 2n=16, represents that the diploid number of chromosomes is 16.
- During meiosis, the primary spermatocyte undergoes the first meiotic division, which separates homologous chromosomes.
- The result of this division is two haploid cells called secondary spermatocytes, each containing half the number of chromosomes as the parent cell.
- Since the diploid number of chromosomes is 16, each secondary spermatocyte contains 8 chromosomes.
- Each chromosome consists of two sister chromatids that are connected at the centromere.
- Therefore, the total number of chromatids in each secondary spermatocyte is 16.

Answer:

The total number of chromatids in each of the secondary spermatocyte is 16.
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2n=16 is in primary spermatocyte which is in metaphase of first meiotic division who shall be the total number of chromatids in each of the secondary spermatocyte??? 1)16 2)32 3)24 4)8?
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