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2n=16 is in a primary spermatocyte which is in metaphase of first meiotic division. What shall be the total number of chromatids in each of the secondary spermatocyte?

  • a)
    16

  • b)
    24

  • c)
    32

  • d)
    8

Correct answer is option 'A'. Can you explain this answer?
Verified Answer
2n=16 is in a primary spermatocyte which is in metaphase of first meio...
Secondary spermatocyte contains half the number of chromosomes i.e., 8. Each chromosome has 2 chromatids, therefore, 8 chromosomes will have 16 chromatids in all.

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Most Upvoted Answer
2n=16 is in a primary spermatocyte which is in metaphase of first meio...
Explanation:
A primary spermatocyte contains 2n number of chromosomes which is equal to 16 in this case. During the first meiotic division, the primary spermatocyte undergoes chromosome replication and separation resulting in the formation of two secondary spermatocytes.

Each secondary spermatocyte contains n number of chromosomes which is equal to 8 in this case. Since each chromosome is composed of two sister chromatids, the total number of chromatids in each of the secondary spermatocyte will be:

Total number of chromatids = n x 2

= 8 x 2

= 16

Therefore, the correct answer is option A, i.e., 16.
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