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Stationary waves are set up in air column . Velocity of sound in air is 330 m/s and frequency is 165 Hz . Then distance between the nodes is (a) 2 m (b) 1 m ( c) 0.5 m (d) 4 m?
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Stationary waves are set up in air column . Velocity of sound in air i...
The distance between two nodes is lambda/2..we get lambda as 330/165 =2..so..distance between two nodes will be 2/2 =1m
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Stationary waves are set up in air column . Velocity of sound in air i...
Given:
Velocity of sound in air (v) = 330 m/s
Frequency of sound (f) = 165 Hz

Formula:
The velocity of sound in a stationary wave is given by the equation:
v = 2Lf

Where:
v = velocity of sound
L = distance between two consecutive nodes (or antinodes) in the stationary wave
f = frequency of sound

Calculation:
We can rearrange the formula to find the distance between the nodes:
L = v / (2f)

Substituting the given values:
L = 330 m/s / (2 * 165 Hz)
L = 330 m/s / 330 Hz
L = 1 m

Therefore, the distance between the nodes in the stationary wave is 1 m.

Answer:
The distance between the nodes is (b) 1 m.
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Stationary waves are set up in air column . Velocity of sound in air is 330 m/s and frequency is 165 Hz . Then distance between the nodes is (a) 2 m (b) 1 m ( c) 0.5 m (d) 4 m?
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