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The moleucular weight of NaCl (degree of dissociation= x) determined by the osmotic pressure method, is found to be different from its actual molecular wieght (M). Which of the following relationship is correct ?
  • a)
    Obs mol wt. = (1+ x)M 
  • b)
    M = (1+ x)×Obs mol. wt.
  • c)
    Obs mol wt. = x×M
  • d)
    M = x×obs mol.wt
Correct answer is option 'B'. Can you explain this answer?
Most Upvoted Answer
The moleucular weight of NaCl (degree of dissociation= x) determined b...
Explanation:

The osmotic pressure method is used to determine the molecular weight of a solute (in this case, NaCl) by measuring the pressure required to prevent the flow of water through a semipermeable membrane. The molecular weight obtained by this method is known as the observed molecular weight.

However, in reality, NaCl does not exist as a single molecule in solution, but rather as ions (Na+ and Cl-) that are dissociated from each other. The extent of dissociation is given by the degree of dissociation (x).

The actual molecular weight of NaCl is M, which is the sum of the atomic weights of sodium and chlorine.

Now, the relationship between the observed molecular weight and the actual molecular weight can be described as follows:

- The observed molecular weight is equal to the actual molecular weight multiplied by (1 - x). This is because the observed molecular weight is lower than the actual molecular weight due to the presence of dissociated ions that contribute to the osmotic pressure. Thus, the formula is:

Observed molecular weight = (1 - x) x Actual molecular weight

- Therefore, the correct option is B, which states that M = (1 - x) x Observed molecular weight.
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The moleucular weight of NaCl (degree of dissociation= x) determined by the osmotic pressure method, is found to be different from its actual molecular wieght (M). Which of the following relationship is correct ?a)Obs mol wt. = (1+ x)M b)M = (1+ x)×Obs mol. wt.c)Obs mol wt. = x×Md)M = x×obs mol.wtCorrect answer is option 'B'. Can you explain this answer?
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