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The moleucular weight of NaCl (degree of dissociation= x) determined by the osmotic pressure method, is found to be different from its actual molecular wieght (M). Which of the following relationship is correct ?a)Obs mol wt. = (1+ x)M b)M = (1+ x)×Obs mol. wt.c)Obs mol wt. = x×Md)M = x×obs mol.wtCorrect answer is option 'B'. Can you explain this answer? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared
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The moleucular weight of NaCl (degree of dissociation= x) determined by the osmotic pressure method, is found to be different from its actual molecular wieght (M). Which of the following relationship is correct ?a)Obs mol wt. = (1+ x)M b)M = (1+ x)×Obs mol. wt.c)Obs mol wt. = x×Md)M = x×obs mol.wtCorrect answer is option 'B'. Can you explain this answer?, a detailed solution for The moleucular weight of NaCl (degree of dissociation= x) determined by the osmotic pressure method, is found to be different from its actual molecular wieght (M). Which of the following relationship is correct ?a)Obs mol wt. = (1+ x)M b)M = (1+ x)×Obs mol. wt.c)Obs mol wt. = x×Md)M = x×obs mol.wtCorrect answer is option 'B'. Can you explain this answer? has been provided alongside types of The moleucular weight of NaCl (degree of dissociation= x) determined by the osmotic pressure method, is found to be different from its actual molecular wieght (M). Which of the following relationship is correct ?a)Obs mol wt. = (1+ x)M b)M = (1+ x)×Obs mol. wt.c)Obs mol wt. = x×Md)M = x×obs mol.wtCorrect answer is option 'B'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice The moleucular weight of NaCl (degree of dissociation= x) determined by the osmotic pressure method, is found to be different from its actual molecular wieght (M). Which of the following relationship is correct ?a)Obs mol wt. = (1+ x)M b)M = (1+ x)×Obs mol. wt.c)Obs mol wt. = x×Md)M = x×obs mol.wtCorrect answer is option 'B'. Can you explain this answer? tests, examples and also practice NEET tests.