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The molecular weight of NaCl (degree of diss. = x) determined by the osmotic pressure method, is found to be different from its actual molecular weight (M). Which of the following relationships is correct ?a)Obs. mol. wt. = (1 + x) Mb)M =(1 + x) × Obs. mol. wt.c)Obs. mol. wt. = x × Md)M = x × Obs. mol. wt.Correct answer is option 'B'. Can you explain this answer? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about The molecular weight of NaCl (degree of diss. = x) determined by the osmotic pressure method, is found to be different from its actual molecular weight (M). Which of the following relationships is correct ?a)Obs. mol. wt. = (1 + x) Mb)M =(1 + x) × Obs. mol. wt.c)Obs. mol. wt. = x × Md)M = x × Obs. mol. wt.Correct answer is option 'B'. Can you explain this answer? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The molecular weight of NaCl (degree of diss. = x) determined by the osmotic pressure method, is found to be different from its actual molecular weight (M). Which of the following relationships is correct ?a)Obs. mol. wt. = (1 + x) Mb)M =(1 + x) × Obs. mol. wt.c)Obs. mol. wt. = x × Md)M = x × Obs. mol. wt.Correct answer is option 'B'. Can you explain this answer?.

Solutions for The molecular weight of NaCl (degree of diss. = x) determined by the osmotic pressure method, is found to be different from its actual molecular weight (M). Which of the following relationships is correct ?a)Obs. mol. wt. = (1 + x) Mb)M =(1 + x) × Obs. mol. wt.c)Obs. mol. wt. = x × Md)M = x × Obs. mol. wt.Correct answer is option 'B'. Can you explain this answer? in English & in Hindi are available as part of our courses for NEET. Download more important topics, notes, lectures and mock test series for NEET Exam by signing up for free.

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