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Some quantity of electricity is used to liberate iodine at anode and a metal at cathode.0.617g metal was deposited and iodine was completely reduced by 46.3ml of 0.124 molar sodium thiosulphate solution.what is the equivalent mass of metal ? A. 12g B. 107g C. 64g D. 38g?
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Some quantity of electricity is used to liberate iodine at anode and a...
Calculation of Equivalent Mass of Metal:
Given Data:
- Mass of metal deposited = 0.617g
- Volume of 0.124 molar Na2S2O3 solution used to reduce iodine = 46.3ml
Step 1: Calculate the moles of iodine reduced
- Moles of iodine = Molarity * Volume (in liters)
- Moles of iodine = 0.124 mol/L * 0.0463 L
- Moles of iodine = 0.00574 mol
Step 2: Calculate the moles of metal deposited
- Moles of metal = Moles of iodine (since they are in 1:1 ratio)
- Moles of metal = 0.00574 mol
Step 3: Calculate the molar mass of the metal
- Molar mass of metal = Mass of metal deposited / Moles of metal
- Molar mass of metal = 0.617g / 0.00574 mol
- Molar mass of metal ≈ 107.6 g/mol
Step 4: Calculate the equivalent mass of metal
- Equivalent mass = Molar mass / Valency
- Since the metal was deposited at the cathode, its valency is 1
- Equivalent mass = 107.6 g/mol / 1
- Equivalent mass ≈ 107g
Therefore, the equivalent mass of the metal deposited is approximately 107g. Hence, the correct answer is option B.
Given Data:
- Mass of metal deposited = 0.617g
- Volume of 0.124 molar Na2S2O3 solution used to reduce iodine = 46.3ml
Step 1: Calculate the moles of iodine reduced
- Moles of iodine = Molarity * Volume (in liters)
- Moles of iodine = 0.124 mol/L * 0.0463 L
- Moles of iodine = 0.00574 mol
Step 2: Calculate the moles of metal deposited
- Moles of metal = Moles of iodine (since they are in 1:1 ratio)
- Moles of metal = 0.00574 mol
Step 3: Calculate the molar mass of the metal
- Molar mass of metal = Mass of metal deposited / Moles of metal
- Molar mass of metal = 0.617g / 0.00574 mol
- Molar mass of metal ≈ 107.6 g/mol
Step 4: Calculate the equivalent mass of metal
- Equivalent mass = Molar mass / Valency
- Since the metal was deposited at the cathode, its valency is 1
- Equivalent mass = 107.6 g/mol / 1
- Equivalent mass ≈ 107g
Therefore, the equivalent mass of the metal deposited is approximately 107g. Hence, the correct answer is option B.
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Some quantity of electricity is used to liberate iodine at anode and a metal at cathode.0.617g metal was deposited and iodine was completely reduced by 46.3ml of 0.124 molar sodium thiosulphate solution.what is the equivalent mass of metal ? A. 12g B. 107g C. 64g D. 38g?
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Some quantity of electricity is used to liberate iodine at anode and a metal at cathode.0.617g metal was deposited and iodine was completely reduced by 46.3ml of 0.124 molar sodium thiosulphate solution.what is the equivalent mass of metal ? A. 12g B. 107g C. 64g D. 38g? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about Some quantity of electricity is used to liberate iodine at anode and a metal at cathode.0.617g metal was deposited and iodine was completely reduced by 46.3ml of 0.124 molar sodium thiosulphate solution.what is the equivalent mass of metal ? A. 12g B. 107g C. 64g D. 38g? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Some quantity of electricity is used to liberate iodine at anode and a metal at cathode.0.617g metal was deposited and iodine was completely reduced by 46.3ml of 0.124 molar sodium thiosulphate solution.what is the equivalent mass of metal ? A. 12g B. 107g C. 64g D. 38g?.
Some quantity of electricity is used to liberate iodine at anode and a metal at cathode.0.617g metal was deposited and iodine was completely reduced by 46.3ml of 0.124 molar sodium thiosulphate solution.what is the equivalent mass of metal ? A. 12g B. 107g C. 64g D. 38g? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about Some quantity of electricity is used to liberate iodine at anode and a metal at cathode.0.617g metal was deposited and iodine was completely reduced by 46.3ml of 0.124 molar sodium thiosulphate solution.what is the equivalent mass of metal ? A. 12g B. 107g C. 64g D. 38g? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Some quantity of electricity is used to liberate iodine at anode and a metal at cathode.0.617g metal was deposited and iodine was completely reduced by 46.3ml of 0.124 molar sodium thiosulphate solution.what is the equivalent mass of metal ? A. 12g B. 107g C. 64g D. 38g?.
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