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A field was supplied water from an irrigation tank at a rate of 120 L/s to irrigate an area of 2.5 ha. The duration of irrigation is 8 h. It was found that the actual delivery at the field, which is about 4 km from the tank, was 100 L/s. The runoff loss in the field was estimated as 800 m3. Then the application efficiency will be
- a)62 %
- b)72 %
- c)76 %
- d)80 %
Correct answer is option 'B'. Can you explain this answer?
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A field was supplied water from an irrigation tank at a rate of 120 L/...
Answer : b)72 %
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A field was supplied water from an irrigation tank at a rate of 120 L/...
Given information:
- Rate of water supplied from irrigation tank = 120 L/s
- Area of the field to be irrigated = 2.5 ha
- Duration of irrigation = 8 hours
- Actual delivery at the field = 100 L/s
- Runoff loss in the field = 800 m3
Calculating the water supplied:
To calculate the total water supplied to the field, we need to multiply the rate of water supplied by the duration of irrigation:
Total water supplied = Rate of water supplied × Duration of irrigation
= 120 L/s × 8 hours
= 960 L
Calculating the area of the field in square meters:
1 hectare = 10,000 square meters
So, the area of the field in square meters = 2.5 ha × 10,000 m2/ha
= 25,000 m2
Calculating the volume of water required:
To calculate the volume of water required to irrigate the field, we need to multiply the area of the field by the depth of irrigation:
Volume of water required = Area of the field × Depth of irrigation
= 25,000 m2 × 1 m (since 1 ha = 10,000 m2)
= 25,000 m3
Calculating the application efficiency:
Application efficiency is the ratio of the actual volume of water used for irrigation to the total volume of water supplied:
Application efficiency = (Actual volume of water used / Total volume of water supplied) × 100
Calculating the actual volume of water used:
The actual volume of water used is the total volume of water supplied minus the runoff loss:
Actual volume of water used = Total volume of water supplied - Runoff loss
= 960 L - 800 m3 (1 m3 = 1000 L)
= 960 L - 800,000 L
= -799,040 L
Calculating the application efficiency:
Application efficiency = (-799,040 L / 960 L) × 100
= -832.58%
Since the calculated application efficiency is negative, it implies that the volume of water used is less than the total volume of water supplied. This is not possible in a practical scenario. Therefore, there seems to be an error in the given information or calculation.
Hence, the provided correct answer (Option B) of 72% for the application efficiency is not accurate based on the given information.
- Rate of water supplied from irrigation tank = 120 L/s
- Area of the field to be irrigated = 2.5 ha
- Duration of irrigation = 8 hours
- Actual delivery at the field = 100 L/s
- Runoff loss in the field = 800 m3
Calculating the water supplied:
To calculate the total water supplied to the field, we need to multiply the rate of water supplied by the duration of irrigation:
Total water supplied = Rate of water supplied × Duration of irrigation
= 120 L/s × 8 hours
= 960 L
Calculating the area of the field in square meters:
1 hectare = 10,000 square meters
So, the area of the field in square meters = 2.5 ha × 10,000 m2/ha
= 25,000 m2
Calculating the volume of water required:
To calculate the volume of water required to irrigate the field, we need to multiply the area of the field by the depth of irrigation:
Volume of water required = Area of the field × Depth of irrigation
= 25,000 m2 × 1 m (since 1 ha = 10,000 m2)
= 25,000 m3
Calculating the application efficiency:
Application efficiency is the ratio of the actual volume of water used for irrigation to the total volume of water supplied:
Application efficiency = (Actual volume of water used / Total volume of water supplied) × 100
Calculating the actual volume of water used:
The actual volume of water used is the total volume of water supplied minus the runoff loss:
Actual volume of water used = Total volume of water supplied - Runoff loss
= 960 L - 800 m3 (1 m3 = 1000 L)
= 960 L - 800,000 L
= -799,040 L
Calculating the application efficiency:
Application efficiency = (-799,040 L / 960 L) × 100
= -832.58%
Since the calculated application efficiency is negative, it implies that the volume of water used is less than the total volume of water supplied. This is not possible in a practical scenario. Therefore, there seems to be an error in the given information or calculation.
Hence, the provided correct answer (Option B) of 72% for the application efficiency is not accurate based on the given information.
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A field was supplied water from an irrigation tank at a rate of 120 L/s to irrigate an area of 2.5 ha. The duration of irrigation is 8 h. It was found that the actual delivery at the field, which is about 4 km from the tank, was 100 L/s. The runoff loss in the field was estimated as 800 m3. Then the application efficiency will bea)62 %b)72 %c)76 %d)80 %Correct answer is option 'B'. Can you explain this answer?
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A field was supplied water from an irrigation tank at a rate of 120 L/s to irrigate an area of 2.5 ha. The duration of irrigation is 8 h. It was found that the actual delivery at the field, which is about 4 km from the tank, was 100 L/s. The runoff loss in the field was estimated as 800 m3. Then the application efficiency will bea)62 %b)72 %c)76 %d)80 %Correct answer is option 'B'. Can you explain this answer? for GATE 2024 is part of GATE preparation. The Question and answers have been prepared according to the GATE exam syllabus. Information about A field was supplied water from an irrigation tank at a rate of 120 L/s to irrigate an area of 2.5 ha. The duration of irrigation is 8 h. It was found that the actual delivery at the field, which is about 4 km from the tank, was 100 L/s. The runoff loss in the field was estimated as 800 m3. Then the application efficiency will bea)62 %b)72 %c)76 %d)80 %Correct answer is option 'B'. Can you explain this answer? covers all topics & solutions for GATE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A field was supplied water from an irrigation tank at a rate of 120 L/s to irrigate an area of 2.5 ha. The duration of irrigation is 8 h. It was found that the actual delivery at the field, which is about 4 km from the tank, was 100 L/s. The runoff loss in the field was estimated as 800 m3. Then the application efficiency will bea)62 %b)72 %c)76 %d)80 %Correct answer is option 'B'. Can you explain this answer?.
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