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A star will appear blue, if the wavelength of maximum emission is in the range 450 to 490 nm. The range of temperature corresponding to which a star will appear blue, will be (Wien’s constant b = 2.897 x 10-3mK) 
  • a)
    6437.8 K to 5912 K
  • b)
    3437 K to 6000 K
  • c)
    3218.4 K to 2956 K
  • d)
    none of these
Correct answer is option 'A'. Can you explain this answer?
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A star will appear blue, if the wavelength of maximum emission is in t...
's Law) is given by the equation:

λ_max = (b / T)

where λ_max is the wavelength of maximum emission, b is Wien's constant (2.8978 x 10^-3 m*K), and T is the temperature in Kelvin.

To find the range of temperature corresponding to a star appearing blue, we can rearrange the equation as follows:

T = b / λ_max

Using the given range of wavelength (450 to 490 nm), we can convert it to meters:

λ_min = 450 nm = 450 x 10^-9 m
λ_max = 490 nm = 490 x 10^-9 m

Now we can calculate the corresponding range of temperature:

T_min = b / λ_max = (2.8978 x 10^-3 m*K) / (490 x 10^-9 m) = 5918 K
T_max = b / λ_min = (2.8978 x 10^-3 m*K) / (450 x 10^-9 m) = 6430 K

Therefore, the range of temperature corresponding to a star appearing blue is approximately 5918 K to 6430 K.
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A star will appear blue, if the wavelength of maximum emission is in the range 450 to 490 nm. The range of temperature corresponding to which a star will appear blue, will be (Wien’s constant b = 2.897 x 10-3mK)a)6437.8 K to 5912 Kb)3437 K to 6000 Kc)3218.4 K to 2956 Kd)none of theseCorrect answer is option 'A'. Can you explain this answer?
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